Dec 29, 2021 #2 skeeter Messages 1,103 Reaction score 1 $\bigg[(2+2\sqrt{2})^2 \cdot (6-4\sqrt{2}) \bigg]^{1/6}$ $\bigg[2(6+4\sqrt{2})(6-4\sqrt{2}) \bigg]^{1/6}$ $\bigg[2(36-32) \bigg]^{1/6}$ $\bigg[2^3\bigg]^{1/6} = \sqrt{2}$
$\bigg[(2+2\sqrt{2})^2 \cdot (6-4\sqrt{2}) \bigg]^{1/6}$ $\bigg[2(6+4\sqrt{2})(6-4\sqrt{2}) \bigg]^{1/6}$ $\bigg[2(36-32) \bigg]^{1/6}$ $\bigg[2^3\bigg]^{1/6} = \sqrt{2}$