The celebrated Hong-Ou-Mandel interferometric effect

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SUMMARY

The Hong-Ou-Mandel (HOM) interferometric effect demonstrates that the expectation value of the product of the number operators, \(\left\langle{N_{a_{1}}}{N_{b_{1}}}\right\rangle\), is zero when two indistinguishable photons enter a beam splitter. This result occurs because the photons interfere destructively, leading to the conclusion that they do not appear simultaneously at both detectors. The expectation value represents the average intensity detected, which aligns with the HOM effect's prediction of photon bunching, resulting in a 50-50 detection probability at either detector but an overall expectation value of zero.

PREREQUISITES
  • Quantum optics fundamentals
  • Understanding of beam splitter behavior
  • Familiarity with photon number operators
  • Basic knowledge of expectation values in quantum mechanics
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Quantum physicists, optical engineers, and students studying quantum mechanics who are interested in the principles of photon interference and the implications of the Hong-Ou-Mandel effect in experimental setups.

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Homework Statement



Determine the expectation values of the product of the number operators

\left\langle{N_{a_{1}}}{N_{b_{1}}}\right\rangle


Explain your result.

Homework Equations



http://en.wikipedia.org/wiki/Hong-Ou-Mandel_effect


The Attempt at a Solution



I've got the expectation value as zero, and I've been told that is correct but i can't explain how. The N_a and N_b refer to the two photons or modes after the beam splitter (i think)(mode zero would be before the beam splitter) so i don't know why they seem to disappear after the beam splitter and why the expectation value (is this the average value of the intensity at one of the detectors?) is zero. I would have expected it to be either:

1 - because of the HOM effect the two input photons will merge into one photon with double intensity and since there are two detectors, and the odds of being detected at either is 50-50, the average value at either is half of 2 = 1.

Or

2 - This is if the expectation value only takes into account one of the detectors when the doubled intensity photon is detected..maybe?
 
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Here is the maple file i have used if anyone wants to look...
 

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