(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

A toboggan is initially moving at a constant velocity along a snowy horizontal surface where friction is negligible. When a pulling force is applied parallel to the ground over a certain distance, the kinetic energy increases by 47%. By what percentage woud the kinetic energy have changed if the pulling force had been at an angle of 38 degrees above the horizontal?

2. Relevant equations

since work is the change in kinetic energy:

w=(Fcos[tex]\theta[/tex] )([tex]\Delta[/tex]d)

3. The attempt at a solution

w=(Fcos[tex]\theta[/tex] )([tex]\Delta[/tex]d)

0.47 = (Fcos1)(1)

0.47 = F

next

W = (0.47cos38)(1)

= 0.37

Is 37% percent change the correct answer? The one shown in my text book is 16%, im pretty sure it wrong unless im doing this all wrong.

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# Homework Help: The change in kinetic energy if distance is constant but angle of force changes.

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