From my very limited knowledge of calculus I would have thought that if mass is assumed constant d/dt (1/2mv^2) = 1/2m2v. This seems to be corroborated by one website http://www.newton.dep.anl.gov/askasci/phy05/phy05008.htm and seems to follow the general rule d/dt (x^n) = nx^(n-1)(adsbygoogle = window.adsbygoogle || []).push({});

However in the Feynman lectures (Volume 1 13-1 (13.2)) http://student.fizika.org/~jsisko/K...Vol 1 Ch 13 - Work and Potential Energy 1.pdf he states that if mass is assumed constant d/dt (1/2mv^2) = 1/2m2v(dv/dt).

Could someone help explain what I have most likely misunderstood?

**Physics Forums - The Fusion of Science and Community**

# The derivative of Kinetic Energy

Know someone interested in this topic? Share a link to this question via email,
Google+,
Twitter, or
Facebook

Have something to add?

- Similar discussions for: The derivative of Kinetic Energy

Loading...

**Physics Forums - The Fusion of Science and Community**