The effect of a dielectric on energy storage of a capacitor

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SUMMARY

The discussion centers on calculating the required volume of a parallel-plate capacitor to store 120 kJ of energy, both with and without a dielectric. The user successfully determined that an air-gap capacitor requires a minimum volume of 3012 m3 to store the energy. However, they encountered difficulties when attempting to calculate the volume needed for a dielectric with a dielectric strength of 3.40 x 108 V/m and a dielectric constant of 5.50, indicating a conceptual misunderstanding in applying the electric field relationship.

PREREQUISITES
  • Understanding of capacitor energy storage equations, specifically U=(1/2)*ε0*E2*VOL
  • Knowledge of dielectric materials and their properties, including dielectric strength and dielectric constant
  • Familiarity with electric field calculations, particularly E=E0/k
  • Basic principles of parallel-plate capacitor design
NEXT STEPS
  • Research the impact of dielectric materials on capacitor performance and energy storage
  • Study the derivation and application of the energy storage equation for capacitors
  • Learn about the limitations and breakdown points of various dielectric materials
  • Explore advanced capacitor design techniques for energy storage in pulsed laser applications
USEFUL FOR

Engineering interns, electrical engineers, and students studying capacitor design and energy storage systems, particularly in applications involving pulsed lasers.

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Homework Statement



You are an intern at an engineering company that makes capacitors used for energy storage in pulsed lasers. Your manager asks your team to construct a parallel-plate, air-gap capacitor that will store 120 kJ of energy.

(a) What minimum volume is required between the plates of the capacitor?

(b) Suppose you have developed a dielectric that has a dielectric strength of 3.40 x 108V/m and has a dielectric constant of 5.50. What volume of this dielectric, between the plates of the capacitor, is required for it to be able to store 120 kJ of energy?

Homework Equations



U=(1/2)*[tex]\epsilon[/tex]0*E2*VOL

The Attempt at a Solution



I got part (a) by plugging in 120 kJ into U and the dielectric break down of air into Emax and solved for volume. turned out to be 3012 m3.

I tried to do the same thing for par (b) but it didn't work. Then I realized that it probably wouldn't be necessary to charge the capacitor such that the electric field is at the dielectric breakdown point to be able to store 120kJ. So I tried to insert the new electric field due to the dielectric (using the relationship E=E0/k where E0 is the electric field before the dielectric is in place and k is the dielectric constant) being put into place and then solving for the volume, however, this still did not yield the correct answer. I have a feeling that there is some conceptual gap in my thought process, but I cannot see it right now, and this is due at midnight and I'm kinda stressed so that's not helping either. Can anyone help point me in the right direction? Any help is appreciated
 
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