The Energy-Momentum Tensor

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SUMMARY

The discussion centers on the equivalence of the stress-energy tensor in General Relativity (GR) and the energy-momentum tensor in Quantum Field Theory (QFT). The stress-energy tensor is defined in GR as $$T_{\mu\nu}=\frac{2}{\sqrt{-g}}\frac{\delta(\mathcal{L} \sqrt{-g})}{\delta g_{\mu\nu}}$$, while in QFT, it is given by $$T^{\mu\nu}=\frac{\partial\mathcal{L}}{\partial( \partial_\mu\phi_{a})}\partial^\nu\phi_a -g^{\mu\nu}\mathcal{L}$$. While both tensors lead to the same energy-momentum 4-vector, they are not generally equivalent. The Belinfante–Rosenfeld stress-energy tensor provides a modified version that aligns with the Hilbert stress-energy tensor used in GR.

PREREQUISITES
  • Understanding of Einstein Field Equations in General Relativity
  • Familiarity with Quantum Field Theory (QFT) concepts
  • Knowledge of Lagrangian mechanics
  • Basic grasp of tensor calculus
NEXT STEPS
  • Study the derivation of the Belinfante–Rosenfeld stress-energy tensor
  • Explore the implications of the Hilbert stress-energy tensor in General Relativity
  • Learn about the conservation laws related to energy-momentum tensors
  • Investigate the differences between canonical and symmetrical energy-momentum tensors
USEFUL FOR

Physicists, particularly those specializing in General Relativity and Quantum Field Theory, as well as students seeking to deepen their understanding of energy-momentum tensors and their applications in theoretical physics.

agostino981
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I am a bit confused here.

In the Einstein Field Equation, there is a tensor called stress-energy tensor in wikipedia and energy-momentum tensor in some books or papers which is $$T_{\mu\nu}=\frac{2}{\sqrt{-g}}\frac{\delta(\mathcal{L} \sqrt{-g})}{\delta g_{\mu\nu}}$$

Is it equivalent to the energy-momentum tensor I came across in QFT?

$$T^{\mu\nu}=\frac{\partial\mathcal{L}}{\partial( \partial_\mu\phi_{a})}\partial^\nu\phi_a -g^{\mu\nu}\mathcal{L}$$

Thanks in advance.
 
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agostino981 said:
I am a bit confused here.

In the Einstein Field Equation, there is a tensor called stress-energy tensor in wikipedia and energy-momentum tensor in some books or papers which is $$T_{\mu\nu}=\frac{2}{\sqrt{-g}}\frac{\delta(\mathcal{L} \sqrt{-g})}{\delta g_{\mu\nu}}$$
This is the general definition of the SYMMETRICAL energy-momentum tensor.

$$T^{\mu\nu}=\frac{\partial\mathcal{L}}{\partial( \partial_\mu\phi_{a})}\partial^\nu\phi_a -g^{\mu\nu}\mathcal{L}$$
Thanks in advance.

This is the CANONICAL energy-momentum tensor. For scalar fields, the two are identical. For other fields they differ by a total divergence. They are equivalent in the sense that both leads to the same energy-momentum 4-vector
P^{ \mu } = \int d^{ 3 } x T^{ 0 \mu } ( x )
 
agostino981 said:
I am a bit confused here.

In the Einstein Field Equation, there is a tensor called stress-energy tensor in wikipedia and energy-momentum tensor in some books or papers which is $$T_{\mu\nu}=\frac{2}{\sqrt{-g}}\frac{\delta(\mathcal{L} \sqrt{-g})}{\delta g_{\mu\nu}}$$

Is it equivalent to the energy-momentum tensor I came across in QFT?

$$T^{\mu\nu}=\frac{\partial\mathcal{L}}{\partial( \partial_\mu\phi_{a})}\partial^\nu\phi_a -g^{\mu\nu}\mathcal{L}$$

Thanks in advance.

They are not, in general, the same. However, in QFT, the stress-energy tensor is not unique, because you can add additional terms to it that have no effect on conservation laws. There is a procedure for tweaking the canonical stress-energy tensor to get a modified tensor, the Belinfante–Rosenfeld stress–energy tensor, that (according to Wikipedia, at least) agrees with the Hilbert stress-energy tensor used by General Relativity:
http://en.wikipedia.org/wiki/Belinfante–Rosenfeld_stress–energy_tensor
 
Wald has a good discussion of this, and shows that the first form arises naturalliy from formulating GR as a Lagrangian theory.
 
Thanks! That clears things up.
 

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