The energy stored in an inductor

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SUMMARY

The discussion centers on the energy storage capabilities of inductors, specifically addressing the misconception that inductors can store energy like batteries. It is established that an inductor stores energy in its magnetic field, represented by the formula E = 1/2*L*I. When an inductor is isolated from a circuit, it cannot maintain energy without a current flow, leading to a high voltage and potential sparking. The conversation also explores the implications of using superconductors to maintain current flow and magnetic fields in inductors.

PREREQUISITES
  • Understanding of electromagnetic theory and inductance
  • Familiarity with the formula for energy stored in an inductor (E = 1/2*L*I)
  • Knowledge of circuit behavior when inductors are connected and disconnected
  • Basic principles of superconductivity and its effects on electrical resistance
NEXT STEPS
  • Research the behavior of inductors in RL circuits and transient analysis
  • Study the principles of superconductivity and its applications in energy storage
  • Explore practical applications of inductors in energy systems, such as in renewable energy storage
  • Learn about the effects of resistive losses in inductive circuits and methods to minimize them
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Electrical engineers, physics students, and anyone interested in energy storage technologies and the principles of inductors in electrical circuits.

scoutfai
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I knew the textbook says the inductor store energy in magnetic field. The typical way they demonstrate this is by setting up a circuit, where a battery is parallel connected to a light bulb and an inductor. At the beginning, the light bulb lights up. Then the battery is cut off and the light bulb doesn't instantly turned off but slowly dimming until it is completely die out. This experiment shows that the inductor store energy.

Okay I am fine with this demonstration and I also agree inductor store energy.

But, can inductor store energy like a battery does?

I think is better if I can illustrate a situation as follow:
Now, imagine you connect only an inductor to a battery. So now the inductor slowly build up its magnetic field until the current flow reaches maximum value. Then suddenly, you take away the inductor (completely isolating it, i.e. the two terminals not connect with anything), put it at somewhere else, keep it like that for some duration (few seconds, minutes, hours, days, etc). After that, you take that inductor, connect the terminals to a light bulb, will the light bulb emits light?
 
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What is the energy stored in an inductor? Look at the expression.
 
No, you can't do i that way. Breaking the current path in an inductor will cause a high voltage over the inductor and a spark between the two terminals.

What you can do is short circuit the inductor, causing the current flow to maintain stable. Then you can store energy in it. But unless you have a superconductor, resistive losses will drain the energy form it pretty fast.
 
What you can do is short circuit the inductor, causing the current flow to maintain stable. Then you can store energy in it. But unless you have a superconductor, resistive losses will drain the energy form it pretty fast.
Yes, and this is really done like this, in a lab of course. But it is a promising method of storing energy, i.e. from solar cells to use at night.
 
gnurf said:
What is the energy stored in an inductor? Look at the expression.
E = 1/2*L*I
Are you trying to say if there is no current flowing in the inductor (when it is isolated), there will be no energy stored in the inductor, and hence the light bulb will not emit light?

But energy has already stored in it before it is isolated. Then, after it is isolated, if it is not capable of keeping that energy, where the energy goes (since energy is conserved)?
 
SirAskalot said:
No, you can't do i that way. Breaking the current path in an inductor will cause a high voltage over the inductor and a spark between the two terminals.

What you can do is short circuit the inductor, causing the current flow to maintain stable. Then you can store energy in it. But unless you have a superconductor, resistive losses will drain the energy form it pretty fast.
what exactly happens during the spark and after that?
When there is a spark, I think it means during that split second, the two terminals are considered "connected" and current flow during that split second. Then, does the spark causes all the energy in the inductor transformed into heat and that is the end of the story?

About the inductor and wire made of superconductor, I think it is a great idea, but I am not exactly understand what is happening.
Let's assume at the time the current from battery is cut off, the terminals of the inductor is shorted simultaneously. So, no current, magnetic field in solenoid starts to decrease, a change in magnetic flux. A change in magnetic flux causes a current to flow in the shorted inductor circuit, since it is a superconductor, current flows forever. With current keep flowing, magnetic field in solenoid maintains. Hence, can I say that originally before the inductor is shorted, if the magnetic field is B in it, then the magnetic field after it is shorted is B-b , where b is a very small value.
Or do you think before and after the inductor is shorted, magnetic field doesn't change?
 
Last edited:
Inductor: U=L*di/dt

From this you can see that if the current is cut of instantaneous the voltage over the inductor becomes infinitely. The voltage will make the air conducting and you get a spark, maintaining current flow trough the inductor. The energy stored in the coil will dissipate into heat etc. and that's the end of the story.

If there is no change in current there is no change in magnetic field. Shorting the terminals and a superconducting material will not change the current. And hence the magnetic field stays the same.
 

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