- #1

Violagirl

- 114

- 0

## Homework Statement

Consider an electric dipole in the attached document. At point P, the fields E

_{+}due to q+ and E

_{-}due to q- are:

E

_{+}= kq/(r-a)

^{2}, E

_{-}= -kq/(r+a)

^{2}

Then total field at P is:

E = E

_{+}+ E

_{-}= kq [ 1/(r-a)

^{2}- 1/(r+a)

^{2}] y-hat

## Homework Equations

See question 1.

## The Attempt at a Solution

So this post is just trying to comprehend the example problem above. I don't believe I'm fully understanding electric field. In the problem above, they have a point P without a charge given. They say that the impact of the electric field of +q occurs at a distance of r-a which makes sense if P is a postive charge. But then for -q, it takes place at a distance of r+a. What I don't understand for this, shouldn't it take place at a distance of 2a+r? It seems like it'd be a distance of 2a from Point P. Or are we considering that the electric field is moving towards -q? I'm not sure I understand this problem...