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physmakesme
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The nucleus of 8Be, which consists of 4 protons and 4 neutrons is very unstable and separates into two alpha particles (2 protons and 2 neutrons) what is the force between the two alpha particles if the distance is 5.60*10^-15m
I thought you would just use the formula F=ke*q1*q2/r^2
so I did that and I repeatedly have the wrong answer:
F= (8.99*10^9)(1.60*10^-19)(1.60*10^-19)/(5.60*10^-15)^2= 41.1N
Please tell what am I doing wrong?
I thought you would just use the formula F=ke*q1*q2/r^2
so I did that and I repeatedly have the wrong answer:
F= (8.99*10^9)(1.60*10^-19)(1.60*10^-19)/(5.60*10^-15)^2= 41.1N
Please tell what am I doing wrong?