The formation of blackbody radiation

Click For Summary
SUMMARY

The discussion centers on the formation of blackbody radiation as described by Planck's law. It establishes that incandescent lamps and electric arcs produce spectra closely resembling that of a blackbody due to the near-equilibrium state between radiation and matter. The conversation highlights the importance of transparency in materials, noting that both large volumes of gas and small volumes of solid can emit blackbody-like spectra, provided they are not transparent. The concepts of emissivity and absorptivity are emphasized as critical for understanding radiation heat exchanges and their applications in fields such as combustion modeling.

PREREQUISITES
  • Understanding of Planck's law of blackbody radiation
  • Familiarity with concepts of emissivity and absorptivity
  • Knowledge of radiation heat exchanges
  • Basic principles of thermodynamics
NEXT STEPS
  • Study the derivation and implications of Planck's law
  • Explore the role of emissivity and absorptivity in thermal radiation
  • Investigate radiation heat exchanges in various materials
  • Learn about combustion modeling techniques and their relation to blackbody radiation
USEFUL FOR

Physicists, engineers, and researchers interested in thermal radiation, combustion modeling, and the principles of blackbody emission.

jauram
Messages
2
Reaction score
0
I am puzzled about the formation of blackbody emission (Planck's law). Specifically, we know that such things like incandescent lamps, an electric arc in a gas at high pressure etc. produce a nearly blackbody spectrum of corresponding temperature. Does this mean that in these cases a nearly equilibrium state between radiation and matter is set up? Or how do you explain why the spectra are close to that of a cavity?:confused:
 
Science news on Phys.org
Consider first a cavity with a small hole: the emission is low enough as to not perturb the BB radiation.

Consider now a very large volume of gas. Since the volume is very large, most of the radiations emitted inside the volume will be reabsorbed, only a tiny fraction has chance to escape.

Consider now a small volume of a solid.
This is exactly similar to the large volume of gas, as long as this volume of solid does not become transparent (like a gold foil).
That's why hot iron from a blast furnace also shows a nice BB spectrum.

The key point is "transparency".
See the full theory of radiation heat exchanges for more details.
These notions of emissivity, absorptivity have many applications, for example in combustion modeling.

Michel
 
Last edited:

Similar threads

  • · Replies 29 ·
Replies
29
Views
4K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 19 ·
Replies
19
Views
18K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 3 ·
Replies
3
Views
3K
Replies
8
Views
5K
  • · Replies 23 ·
Replies
23
Views
3K