The frequency(/time period) of oscillation for a 2 body spring system

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SUMMARY

The time period of oscillation for a two-body spring system is defined by the equation T = 2π√((m1*m2)/(m1+m2) * (1/k)), where m1 and m2 are the masses and k is the spring constant. This formula utilizes the concept of reduced mass and is derived using the center of mass reference frame. The derivation can be found in detail in the provided resource from the University of Victoria.

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  • Understanding of classical mechanics principles
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  • Knowledge of oscillatory motion and spring systems
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abelthayil
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Homework Statement



Two masses m1 and m2 are connected by a spring of spring constant k rest on a frictionless surface. If the masses are pulled apart and let go, the time period of oscillation is :

I know the answer is T(time period) = 2∏\sqrt{((m1*m2)/(m1+m2))*1/k}.
Can some one help me derive this equation. I know the concept is called reduced mass and think it uses the center of mass as the reference frame.
 
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