The problem states to calculate the height at which the gravity acceleration is 5x smaller than on the surface of the earth. So
gamma(don't know how to put it :P)=6,67x10^-11
g=gamma x M/(R+h)^2
The Attempt at a Solution
I was pretty confident in this h = sqrt (g x R)/(gamma x M) but the result turned out bad.
The book I use states that the result is 7874 km. [/B]