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The interior design of the central trunk of a ring spaceship
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[QUOTE="Strato Incendus, post: 6838279, member: 698049"] Alright, here's a proposed structure for the central trunk, if we apply a "skyscraper" layout (I put it in a spoiler because of its size): EDIT: I just found out there's no option here of zooming into the image. So a quick explanation, because most of the font is too small: The six grey boxes in the middle are the rotating hubs of the six rings (which create artificial gravity of 0.21 g, whereas there is 1.05 g on the rings themselves). In between every two hubs, there's a distance of 5 m - this is the ceiling height of the rooms placed in between. Each of these are circular rooms with a diameter of 90 m (the diameter of the pipe is 100 m, so there's a gap of 5 m on each side). Only the hangars for smaller spacecraft (one at the front, and one at the back) have a ceiling height of 10 m each. [SPOILER="Image contained"][ATTACH type="full" alt="Central Pipe Inner Structure vertical small.png"]319672[/ATTACH][/SPOILER] The central trunk at this point is [B]1 km[/B] long. [B]I'm wondering whether it would have to be mandatory to use the lifts during the acceleration or braking phase. Otherwise, if you go by foot, you'd risk falling down the entire tunnel at an acceleration of 0.048 m/s².[/B] But let me see if I as a layman can figure out the impact velocity here. The formula I've found was the following: [B]v=Sqrt(2∗g∗h)[/B] So on Earth, if you fell for 1 km, the impact velocity would be 140 m/s. The same applies if you have a skyscraper spaceship that accelerates at 1 g (=9.81 m/s²). With the present acceleration (0.048 m/s²) in space, you'd end up with 2 * 0.048 m/s² * 1000 m = 96 m²/s², the square root of which is 9.80 m/s. In other words, the impact velocity in m/s is, coincidentally, the same value as the mere acceleration in m/s² at 1 g. 9.80 m/s equals about 35.28 km/h, or 21.92 mph. According to a study by Tefft (2013), for a pedestrian getting hit by a car, the average risk of death would already be at 10% at an impact velocity of 24.1 mph, and just 17.1 mph would already be enough for severe injury. So in short: Falling down the central trunk during acceleration or braking, that is, deliberately traversing the entire length of the tunnel by foot, is still a huge no-no. [B]The question remains, though:[/B] If somebody slips, say, during an accident or during combat, and starts falling down the tunnel, they would be accelerating fairly slowly, compared to falling down a shaft on Earth. Meaning, there should still be plenty of time to catch them somewhere along the way, right? Especially since falling the entire length of 1 km will be a rarity: People will probably start falling somewhere in the middle, and will be caught or able to hold on to something, long before they reach the rear end of the tunnel. [/QUOTE]
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The interior design of the central trunk of a ring spaceship
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