1. The sum of the forces FA + FB + FC = 0. The magnitudes of lFAl = 100 N and lFBl = 80N. Graphically determine the magnitude lFCl and the angle α 2. See Attachment 3. The attempts at the solution are as follows: FBx = 80N cos 30° = 69.3 N FBy = 80N sin 30° = 40.0 N FAx = 100N cos 0° = 100 N FAy = 100N sin 0° = 0N After this, I can't figure out what to do, or if I am even on the right track.