The mass of the ball is m, and the length of the string is L

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SUMMARY

The discussion focuses on calculating the difference in tension between the highest point (T1) and the lowest point (T2) of a Yo-Yo ball's motion, where the mass of the ball is denoted as m and the length of the string as L. The initial attempt at a solution yielded T2 - T1 = 2mg, but the correct answer is 6mg. The discrepancy arises from the varying speeds at different positions of the ball, necessitating the application of conservation of energy principles to relate the speeds at the top and bottom of the motion.

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Homework Statement



A man plays a Yo-Yo ball as shown in the figure. The mass of the ball is m, and the length of the string is L. The ball moves in a circle along a vertical plane. What is the difference of the string tension at the lowest point ((T_{2})) and the highest point ((T_{1}))
yo yo.jpg


The Attempt at a Solution



(\frac{mv^{2}}r=T_1+mg=T_2-mg)
\Rightarrow T_2-T_1=2mg
But the answer is 6mg, I guess the problem is that v is not equal at the two different positions. In this case, I don't know how to solve it.
 
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Your guess is correct.
Try to use conservation of energy to relate the top speed with the bottom speed.
 

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