The Meaning of Degenerate in the Context of Linear Algebra

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SUMMARY

The discussion clarifies the concept of degeneracy in linear algebra, specifically regarding the derivative map \(f(x) \rightarrow f'(x)\). It establishes that this map is degenerate on the space of polynomials \(R[x]_{n}\) due to the presence of a non-trivial null space. Conversely, the map is non-degenerate on the span of the functions \(\sin t\) and \(\cos t\), indicating that the derivative map does not have a non-trivial null space in this context.

PREREQUISITES
  • Understanding of linear transformations and their properties
  • Familiarity with the concept of null space in linear algebra
  • Knowledge of polynomial spaces, specifically \(R[x]_{n}\)
  • Basic comprehension of trigonometric functions and their derivatives
NEXT STEPS
  • Study the properties of linear transformations in detail
  • Learn about null spaces and their implications in linear algebra
  • Explore the relationship between derivatives and function spaces
  • Investigate the applications of degenerate and non-degenerate maps in advanced linear algebra
USEFUL FOR

Students in advanced linear algebra courses, educators teaching linear algebra concepts, and mathematicians interested in the properties of linear transformations and their applications.

Sudharaka
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Hi everyone, :)

Here's a question I encountered.

Show that \(f(x)\rightarrow f'(x)\) is degenerate on \(R[x]_{n}\) and is non-degenerate on \(<\sin t,\,\cos t>\)

Don't give me the full answer but explain what is meant by degeneracy in this context.

Thank you.
 
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It means the derivative map has a non-trivial null space.
 
Deveno said:
It means the derivative map has a non-trivial null space.

Thank you very much. Now I understand it perfectly. I am doing an Advanced Linear Algebra course and I am not getting everything perfectly. I think I have to put a lot of effort into it. :)
 

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