The moment of inertia of a rod that is rotating off the end of the rod.

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SUMMARY

The moment of inertia of a thin, uniform density rod rotating about an axis at one end can be calculated using the parallel axis theorem. The moment of inertia of a rod about its center of mass is given by the formula \( \frac{1}{12} m L^2 \), where \( m \) is the mass and \( L \) is the length of the rod. To find the moment of inertia about the end of the rod, apply the parallel axis theorem, which states that \( I = I_{cm} + md^2 \), where \( d \) is the distance from the center of mass to the new axis. For modeling an ice skater's arms as rod-like structures, this approach is essential for accurate calculations.

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  • Basic knowledge of integration techniques
  • Ability to model physical bodies (e.g., cylinders and rods)
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Lewis Edmunds
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Is there a formula for the moment of inertia? A thin, uniform density rod is rotating about an axis that is off the end of the rod, so it looks a bit like this:

------- |
(------- is the rod and | is the axis of rotation, so the rod is rotating out of the plane of your screen)

I just have a problem about an ice skater spinning and moving their arms, and I'm not sure how to work out the moment of inertia of the arms. The problem says to model them as two rod-like arms that are attached to the the outside of the torso (modelled as a cylinder)
 
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Do you know the moment of inertia of a rod about its center of mass? If so, use the parallel axis theorem to find the moment of inertia about the axis that you need.
 
If you don't know the parallel axis theorem, you can find the MMOI directly by integration.
 

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