The Mystery of Equation (3.1.3) and the Origin of the Universe

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The discussion centers on understanding how equation (3.1.3) leads to the conclusion that the initial mass of the universe, M0, is half of the Planck mass, Mp/2. The user attempts to set the universal time T equal to Tp, suggesting that Tp represents the universe's inception. A suggestion is made to consider the initial volume as a sphere defined by the Planck length and to derive the initial mass using the density formula provided. By comparing this derived mass to the standard Planck mass equation, the user may find the expected relationship. The conversation highlights the complexity of relating universal time and mass density in cosmological equations.
bobsan
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Homework Statement
How can we know that the initial mass of the universe was half of the Planck mass from the formula mass density of the Universe as a function of universal time?
Relevant Equations
(ρ reduced)(Tp)^2 = ρT^2
ρ reduced = 3c^5/(4hG^2)
Screen Shot 2022-05-23 at 14.07.18.png

I tried setting the Universal time T = Tp as when T = 0 there was no universe and thought Tp would be the first instance of the universe, but I still can't figure out how equation (3.1.3) implies that M0 = Mp/2
 
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bobsan said:
Homework Statement:: How can we know that the initial mass of the universe was half of the Planck mass from the formula mass density of the Universe as a function of universal time?
Relevant Equations:: (ρ reduced)(Tp)^2 = ρT^2
ρ reduced = 3c^5/(4hG^2)

View attachment 301814
I tried setting the Universal time T = Tp as when T = 0 there was no universe and thought Tp would be the first instance of the universe, but I still can't figure out how equation (3.1.3) implies that M0 = Mp/2
Hi @bobsan. Welcome to PF.

The reasoning in the attachment isn’t clear (well, it's missing actually). Not a familiar area for me but you could try this...

Consider the initial volume to be a sphere with diameter (or possibly radius) equal to the Planck length. Express this volume in terms of ℏ, G and c.

Multiply this by the density as given in equation 3.1.4. This gives you an expression for the initial mass. Compare this expression to the standard formula (expressed in in terms of ℏ, G and c)for the Planck mass.

If you’re lucky, you may find your expression for mass is half the Planck mass. No idea if that’s what’s intended though.
 
Where are you getting this from?
 
I want to find the solution to the integral ##\theta = \int_0^{\theta}\frac{du}{\sqrt{(c-u^2 +2u^3)}}## I can see that ##\frac{d^2u}{d\theta^2} = A +Bu+Cu^2## is a Weierstrass elliptic function, which can be generated from ##\Large(\normalsize\frac{du}{d\theta}\Large)\normalsize^2 = c-u^2 +2u^3## (A = 0, B=-1, C=3) So does this make my integral an elliptic integral? I haven't been able to find a table of integrals anywhere which contains an integral of this form so I'm a bit stuck. TerryW

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