1. The problem statement, all variables and given/known data The figure shows a 230 g uniform rod pivoted at one end. The other end is attached to a horizontal spring. The spring is neither stretched nor compressed when the rod hangs straight down. K=3.0N/m and the length of the rod is 0.20m. What is the rod's oscillation period? You can assume that the rod's angle from vertical is always small. 2. Relevant equations Restorative force=F=-kΔx Torque=Fd=force * length of lever arm Moment of inertia for a rod pivoted about one end: I=(1/3)mL2 Angular frequency(w)=2π/T 3. The attempt at a solution -kΔx=I*-w2Θ <=> -kr2Θ=I*-w2Θ <=> -kr2Θ/I=-w2Θ Substitute I into the equation, L=r in this case. -3K/M*Θ=-w2Θ Therfore w=sqt(3K/M) <=> 2π/T=sqt(3K/M) <=> T=2π/sqt(M/3K)=1.00s But, I don't really know if my calculations are correct.