The period of summation functions

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SUMMARY

The discussion centers on determining the period of summation functions, specifically for expressions like f(t) = ∑ 2^-k * e^(i7kt). Participants explore the application of Fourier series and the use of Euler's formula to find periodicity. The consensus is that the period T can be calculated as T = 2π/7, confirming that ω equals 7k. The definition of periodicity is reiterated, emphasizing that if T is the period, then f(t + T) must equal f(t).

PREREQUISITES
  • Understanding of Fourier series and summation functions
  • Familiarity with Euler's formula and complex exponentials
  • Knowledge of periodic functions and their definitions
  • Basic calculus concepts related to limits and series
NEXT STEPS
  • Study the properties of Fourier series and their applications in signal processing
  • Learn about complex exponential functions and their role in periodicity
  • Explore advanced topics in calculus, focusing on series convergence
  • Investigate the implications of periodicity in different mathematical contexts
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Mathematicians, engineers, and students studying signal processing or complex analysis who seek to deepen their understanding of periodic functions and summation techniques.

Luongo
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1. how do i find the period of summation of some function ie: 2^-k or cos(pi k) multiplied by some complex exponential ei7kt

ie: f( t ) = \sum
2-kei7kt
2. does anyone know the formula for finding the period of summations of complex exponentials? note this is for fourier
3. would i say that omega is 7k by Euler's method. if i converted to sines and cosines, thus the period T = 2pi/7?
is this how i would find the period of this summation?
 
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The definition of periodicity is as follows:
If T is the period of a function f(t) then,
f(t+ T) = f(t).

Does your answer admit to this definition ?
 
╔(σ_σ)╝ said:
The definition of periodicity is as follows:
If T is the period of a function f(t) then,
f(t+ T) = f(t).

Does your answer admit to this definition ?

i think so thanks
 
You are welcome. :-)
 
╔(σ_σ)╝ said:
You are welcome. :-)


my friend said i am wrong...?
 
Luongo said:
my friend said i am wrong...?
What is his reasoning ?
 

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