- #1

rwooduk

- 761

- 59

## Homework Statement

[tex]\omega (q)= \sqrt{( \frac{4f}{m})} sin\frac{qa}{2}[/tex]

## Homework Equations

N/A

## The Attempt at a Solution

I dont understand the linear line given on the graph. For low q (or as q tends to zero) it says the relationship is linear. But as q tends to zero for the given equation I dont see how the equation goes to:

##\omega (q)= qa \sqrt{\frac{f}{m}}##

please could someone explain this, it's not a homework question, just going through the notes we have been given.

thanks in advance for any help

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