The potential electric and vector potential of a moving charge

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SUMMARY

The discussion focuses on the application of the Liénard-Wiechert equations to determine the electric potential and vector potential of a moving charge. The participant presents a condition involving the variables \(vt\), \(r\), and \(b\) to derive the scalar potential \(\phi\) and vector potential \(\vec A\). The equations provided indicate that the electric potential does not necessarily need to propagate at the speed of light, particularly in the context of the Lorenz gauge. The reference to Feynman's Lecture 25, section 25-5, underscores the theoretical foundation of the discussion.

PREREQUISITES
  • Understanding of Liénard-Wiechert equations
  • Familiarity with electric and vector potentials
  • Knowledge of gauge theories, particularly Lorenz gauge
  • Basic grasp of electromagnetic theory and relativistic effects
NEXT STEPS
  • Study the derivation and implications of the Liénard-Wiechert equations
  • Explore the concepts of scalar and vector potentials in electromagnetism
  • Investigate the role of gauge choices in electromagnetic theory
  • Review Feynman's Lectures on Physics, specifically Lecture 25, section 25-5
USEFUL FOR

Physicists, electrical engineers, and students studying electromagnetism, particularly those interested in the dynamics of moving charges and gauge theories.

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I could try to apply the Liénard-WIechert equations immediatally, but i am not sure if i understand it appropriately, so i tried to find by myself, and would like to know if you agree with me.

When the information arrives in ##P##, the particle will be at ##r##, such that this condition need to be satisfied:
$$\frac{(vt-r)^2}{v^2} = \frac{r^2+b^2}{c^2} (1)$$

So, we have $$\phi = \frac{kq}{s} = \frac{kq}{r}$$
Also, $$ \vec A = \frac{\mu}{4\pi} \int \frac{J' dV'}{|r-r'|} = \frac{\mu}{4\pi} \frac{q v}{|r|}$$

such that r satisfies ##(1)##.

Is it right? Do you agree with it? I am asking because i remember to read somewhere that the potential electric not necessarilly need to move at speed of light, but i think this is the case in Lorenz gauge. I haven't assumed any gauge here.
 
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