The probability that one 3 foot section of wire is defective is 0.002.

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Homework Help Overview

The problem involves determining the probability of having 3 or more defective sections of wire, given that the probability of one 3-foot section being defective is 0.002. The context is related to probability theory and statistical distributions.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the interpretation of the defect probability and the total length of wire, questioning how to model the situation. Some suggest using a binomial distribution, while others consider a Poisson approximation.

Discussion Status

The discussion is ongoing, with participants exploring different statistical models and interpretations of the problem. There is no explicit consensus, but several viable approaches have been suggested.

Contextual Notes

Participants note the ambiguity in the problem statement regarding the interpretation of the defect probability and the total number of sections derived from the length of wire.

glebovg
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The probability that one 3 foot section of wire is defective is 0.002. If someone has 450 feet of wire then what is the probability they will have 3 or more 3 feet sections that are defective?
 
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What have you tried?
 


I'm getting the feeling that there isn't enough information here. I think the term "probability that one 3 foot section of wire is defective is 0.002" could be interpreted in a number of ways.
 


cmb said:
I'm getting the feeling that there isn't enough information here. I think the term "probability that one 3 foot section of wire is defective is 0.002" could be interpreted in a number of ways.

I agree it is pretty ambiguous. But one could assume we are talking about dividing the wire into 150 separate 3 foot sections and interpret it that way just to have something to talk about.
 


That is exactly what I think. At first I thought that X~Pois(λ) and that P(X=1)=0.002. But finding λ seems impossible and even the values you find do not make any sense.
 


Perhaps X~Bin(150, 0.002).
 


glebovg said:
Perhaps X~Bin(150, 0.002).
That's what I would try (making an independence assumption).
 


glebovg said:
That is exactly what I think. At first I thought that X~Pois(λ) and that P(X=1)=0.002. But finding λ seems impossible and even the values you find do not make any sense.

Well, you have a large N, small p version of the binomial, with m = N*p "moderate", so I think a Poisson approximation should be very good, indeed.

RGV
 


Thank you.
 

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