The reaction of rusting iron and the heat produced

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SUMMARY

The discussion centers on calculating the heat produced from the rusting of iron, specifically the reaction 4Fe + 3O2 = 2Fe2O3 with a heat change (delta H) of -1.65 x 10^3 kJ. Given 15.7 grams of iron and 7.99 grams of oxygen, the limiting reagent is iron. The calculated heat released is -116 kJ, confirming that the heat is released during the reaction, which is consistent with the negative sign of delta H.

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Homework Statement


4Fe+3O2=2Fe2O3 deltaH=-1.65 x 10^3kJ

If there are 15.7 grams of iron and 7.99 grams of oxygen, how much heat will be produced?


Homework Equations


Since Iron is the limiting reagent do I use that to determine the heat released?



The Attempt at a Solution


15.7gFe x 1molFe/55.9gFe x 1molFe/4molFe x -1.65x10^3kJ/1molFe = -116kJ
 
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Looks OK to me, but think about sign. You are not asked about delta H for the reaction, but about amount of the heat released.
 

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