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The relationship between time taken per oscillation and mass
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[QUOTE="WaterMelllon1, post: 3214524, member: 319471"] In an experiment, a ruler is connected to the table and some weights are bounded to one end of the ruler. The ruler is then flicked and the time taken per oscillation is measured. I have plotted a graph with the data I have collected, with the mass on the y-axis and time on x-axis. The graph produced appears to be a curve. I have tried altering the values on the x-axis; I have squared it, 1 over the square of it, square rooted it, and I found that the graph becomes linear when the values are squared. So the mass should be proportional to 1 over the square of the time taken. I have tried finding out a mathematical relationship for this, but I am not sure if this is correct or not. Well, if we make w=angular velocity, then w=θ/t, with θ being angular displacement and t being the time period. Since θ belongs in a circle, then it is safe to say that w=2π/t (?) Also, if the force of an oscillation is proportional to -displacement (x), then it is true to say that F=-kx, with k being a constant. Since F also = ma, then ma=-kx. According the the simple harmonic wave equation for acceleration is a=-xw[SUP]2[/SUP]sinwt. Since the formula for displacement(x) = x sinwt and a=-w[SUP]2[/SUP](x sinwt), then a=-xw[SUP]2[/SUP] So ma=-kx will become m(-xw[SUP]2[/SUP])=-kx, then using some algebra, m=k/w[SUP]2[/SUP]. Since w=2π/t, then m=kT[SUP]2[/SUP]/4π[SUP]2[/SUP]. Since k/4π[SUP]2[/SUP] is a constant, I can ignore that and say m is proportional to t[SUP]2[/SUP]. Is my reasoning true? I feel like I am wrong in quite a few spots. Thanks for helping [/QUOTE]
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Introductory Physics Homework Help
The relationship between time taken per oscillation and mass
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