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The relationship between Vav and Height of a ball rolling down a slope

  1. Dec 9, 2009 #1
    1. The problem statement, all variables and given/known data
    I have this problem on my physics exam and I hoped you guys could help. The Question is: Why is the relationship between the average velocity and the height of a ball rolling down a slope a square root function?
    The slope is 100cm long, the height of the ball at the top of the slope is 30cm and the angle is 17.45 degrees.

    2. Relevant equations
    S=1/2at2 + viT
    Vav = S/T
    Vav = (Vi + Vf) / 2

    3. The attempt at a solution
    I established that the relation is, in fact, represented by a square root function.
    I figured out the rule of the function, by determining that the A/K is.
    I just have no idea why this is a square root function...
    Is it because the ball reaches its' terminal velocity quicker?
    Or because, when the height is smaller, there is a much smaller acceleration, ultimately decreasing the average velocity?
    Please Help- My exam is on 12/17/09

    Thanks :D

    Attached Files:

  2. jcsd
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