The Speed of a transverse wave

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SUMMARY

The speed of a transverse wave on a copper wire with a cross-sectional area of 1.1 x 10^-6 m² and a linear density of 7.0 x 10^-3 Kg/m is initially 46 m/s. When the temperature is lowered by 14°C, the speed of the wave must be recalculated considering the effects of thermal contraction and tension. Using the formulas v = √(F/(m/L)) and F = Y(∆L/L0)A, where Y is Young's modulus (1.1 x 10^11 N/m²) and α is the coefficient of linear expansion (17 x 10^-6), the new speed can be determined by adjusting for the change in tension due to temperature decrease.

PREREQUISITES
  • Understanding of wave mechanics, specifically transverse waves
  • Familiarity with Young's modulus and its application in tension calculations
  • Knowledge of thermal expansion principles and coefficients
  • Basic algebra for manipulating equations and solving for variables
NEXT STEPS
  • Calculate the initial tension in the wire using the given parameters
  • Determine the new tension after a temperature decrease of 14°C
  • Apply the modified wave speed formula to find the new speed of the wave
  • Explore the impact of different materials on wave speed in similar conditions
USEFUL FOR

Physics students, engineers, and anyone interested in understanding wave dynamics in materials, particularly in applications involving temperature variations and material properties.

golriz
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A copper wire, whose cross sectional area is 1.1 x 10 ^ -6 m^2, has a linear density of 7.0 x 10^-3 Kg/m and is strung between two walls. At the ambient temperature, a transverse wave travels with a speed of 46 m/s on this wire. The coefficient of linear expansion for copper is 17 x 10^-6 , and Youngs modulus for copper is 1.1 x 10^11 N/m^2. What will be the speed of the wave when the temperature is lowered by 14 C?


v = √(F/(m⁄L)) (1)
F = Y(∆L/L0)A (2)
∆L = α.L0.∆T ⇒ ∆L/L0 = α.∆T (3)



A = 1.1 x 10^-6 m^2
m/L = 7 x 10^-3 Kg/m
α = 17 x 10^-6
Y = 1.1 x 10^11 N/m^2
v = 46 m/s




We can write formula (1) such this:

v = √((Y.α.∆T.A)/(m/L))

and now substitute all the variables in the above formula for finding ∆T.
But now I don't know what do I have to do, ∆T2 to find the speed of the wave.
 
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Work out the initial tension in the wire. Then work out the tension after cooling 14 deg. Think of the wire shrinking due to the decrease in temperature but additional tension stretches it back to the original length.

AM
 

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