The time evolution operator (QM) Algebraic properties

Join the discussion
Ask a follow-up here, or get your own question answered by working scientists, mathematicians and engineers — people, not an autocomplete.
Real named experts · corrections over time · the nuance an AI answer skips
2 replies · 2K views
knowlewj01
Messages
100
Reaction score
0

Homework Statement



The hamiltonian for a given interaction is

[itex]H=-\frac{\hbar \omega}{2} \hat{\sigma_y}[/itex]

where

[itex]\sigma_y = \left( \begin{array}{cc} 0 & i \\ -i & 0 \end{array} \right)[/itex]

the pauli Y matrix

Homework Equations

The Attempt at a Solution



So from the time dependent Schrödinger equation we, can take the time dependence and put it into the time evolution operator U(t)

[itex]HU(t)\left|\Psi(r,0)\right>=i\hbar \frac{d}{dt}U(t)\left|\Psi(r,0)\right>[/itex]

becomes

[itex]i\hbar\frac{d}{dt}U(t) = HU(t)[/itex]

so for a non time dependent Hamiltonian H, this means:

[itex]U(t) = e^{-\frac{i}{\hbar}H t}[/itex]

so we have then:

[itex]U(t) = e^{\frac{i\omega t}{2}\hat{\sigma_y}}[/itex]

How do you treat this? Is there any particular identity that allows you to move the operator out of the exponent?
 
Last edited:
Physics news on Phys.org
edit: changed the matrix to the correct form