The train (92m long) starts from rest, constant accel. at t=0s
The car at t=0s just reaches the end of the train. The car is moving at a constant velocity.
At time t=14s the car just reaches the front of the train.
The train eventually pulls ahead of the car, and at t=28s the car is again at the rear of the train. Find the magnitudes of a) the cars velocity b) the trains acceleration
vf=vi + at
Vf^2=Vi^2 + 2ad
The Attempt at a Solution
I calculated the car travelled a distance of 92m in 14s from the rear to the front of the train at constant velocity using v=d/t=92/14=6.57m/s. In another 14s, the car travelling at 6.57m/s will have travelled an additional distance of d=vt=(6.57)(14)=92m for a total distance of 184m in 28s. So the answer i got for a) The cars velocity was 6.57m/s. I know this is wrong, but i do not understand why? Please help?
The trains acceleration i do not know how to figure that out at all.
Please help. thank you.