(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

The train (92m long) starts from rest, constant accel. at t=0s

The car at t=0s just reaches the end of the train. The car is moving at a constant velocity.

At time t=14s the car just reaches the front of the train.

The train eventually pulls ahead of the car, and at t=28s the car is again at the rear of the train. Find the magnitudes of a) the cars velocity b) the trains acceleration

2. Relevant equations

v=d/t

vf=vi + at

Vf^2=Vi^2 + 2ad

d=vit +1/2at^2

3. The attempt at a solution

I calculated the car travelled a distance of 92m in 14s from the rear to the front of the train at constant velocity using v=d/t=92/14=6.57m/s. In another 14s, the car travelling at 6.57m/s will have travelled an additional distance of d=vt=(6.57)(14)=92m for a total distance of 184m in 28s. So the answer i got for a) The cars velocity was 6.57m/s. I know this is wrong, but i do not understand why? Please help?

The trains acceleration i do not know how to figure that out at all.

Please help. thank you.

**Physics Forums | Science Articles, Homework Help, Discussion**

Join Physics Forums Today!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

# Homework Help: The train eventually passes the car

**Physics Forums | Science Articles, Homework Help, Discussion**