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Cosmo Novice said:I am sure someone can elaborate further but as this is off topic you may be better starting a fresh thread.
Will do, thanks ;)
Cosmo Novice said:I am sure someone can elaborate further but as this is off topic you may be better starting a fresh thread.
bcrowell said:Anything outside of our observable universe can certainly be quantified. Just wait a while, and it will be inside our observable universe.
Cosmo Novice said:Well objects that come inside our OU will eventually be outside our OU once their recession >C. So while our OU may be growing now, at some point our OU will begin to shrink. as galaxies at the edge of our OU begin to recede >C.
George Jones said:For a flat universe that exponentially expands for all time, the Hubble radius is the cosmological event horizon, but (as in all universes) we never see anything cross the horizon, so we never see anything on the Hubble sphere.
In our universe, the Hubble sphere and the cosmological event horizon don't correspond, even in the distant future. If we can see galaxy A now, it will never disappear. At some future time, A will be "receding" with a speed greater than the speed of light, but, even after this time, we will see A with (exponentially) increasing redshift, and with increasing faintness. In principle, we will never lose sight of A. In fact, some stuff that we see now (for example, the CMB from the (near) the surface of last scattering) was outside the Hubble sphere when the light we now see started its journey.
George Jones said:I think that you confused the Hubble (sphere) radius with the cosmological event horizon.
Cosmo Novice said:What is a cosmological event horizon?
Cosmo Novice said:What I meant was that our OU will eventually (billions of years) consist of less galaxies as once a distant galaxy receeds>C and all light emiited prior to a recession>C reaches us then we will no longer see said galaxy.
George Jones said:Consider the following two disjoint subsets of spacetime:
Suppose we now see galaxy A. Assume that at time t in the future, A's recession speed is greater than c, and that at this time someone in galaxy A fires a laser pulse directly at us. Even though the pulse is fired directly at us, the proper distance between us and the pulse will initially increase. After a while, however, the pulse will "turn around", and the proper distance between us and the pulse will decrease, and the pulse will reach us, i.e., we still see galaxy A.
Neandethal00 said:Probably not correct.
Neandethal00 said:I argued with a few people in another forum whether photons have inertia or not. Eventually I realized it creates more problems, specially in experimental results with light, if we assume moving frames have no effect on photons.
Which means photons of galaxies receding with FTL speed may be traveling with the galaxies with FTL speed but photons speed inside the galaxy would remain the same c.
Btw, my logical mind says galaxies are not moving at FTL speed.
George Jones said:As I said above this isn't true. It is true that recession speeds of galaxies that we now see will eventually exceed c, but it is not true that we loose sight of a galaxy once its recession speed exceeds c. If we see a galaxy now, then we will (in principle) always see the galaxy, even when its recession speed exceeds c. It might seem that moving to a recession speed of c represents a transition from subset 1) to subset 2), but this isn't the case.
Suppose we now see galaxy A. Assume that at time t in the future, A's recession speed is greater than c, and that at this time someone in galaxy A fires a laser pulse directly at us. Even though the pulse is fired directly at us, the proper distance between us and the pulse will initially increase. After a while, however, the pulse will "turn around", and the proper distance between us and the pulse will decrease, and the pulse will reach us, i.e., we still see galaxy A.
Cosmo Novice said:How will it "turn around" Can you please clarify this point.
O B A C
* * * ** * * *
O B A C
George Jones said:I know this is very counter-intuitive, but I really did mean what I wrote in posts #52 and #55.![]()
Thanks for pushing me for further explanation, as this has forced me to think more conceptually about what happens.
This can happen because the Hubble constant decreases with time (more on this near the end of this post) in the standard cosmological model for our universe. Consider the following diagram:
Code:O B A C * * * * * * * * O B A C
The bottom row of asterisks represents the positions in space (proper distances) of us (O) and galaxies B, A, and C, all at the same instant of cosmic time, t_e. The top row of asterisks represents the positions in space of us (O) and galaxies B, A, and C, all at some later instant of cosmic time, t. Notice that space has "expanded" between times t_e and t.
Suppose that at time t_e: 1) galaxy A has recession speed (from us) greater than c; 2) galaxy A fires a laser pulse directed at us. Also suppose that at time t, galaxy B receives this laser pulse. In other words, the pulse was emitted from A in the bottom row and received by B in the top row. Because B's recession speed at time t_e is greater than c, the pulse fired towards us has actually moved away from us between times t_e and t.
Now, suppose that the distance from us to galaxy B at time t is the same as the distance to galaxy C at time t_e. Even though the distances are the same, the recession speed of B at time t is less than than the recession speed of C at time t_e because:
1) recession speed equals the Hubble constant multiplied by distance;
2) the value of the Hubble constant decreases between times t_e and t.
Since B's recession speed at time t_e is greater than c, galaxy C's recession speed at time t_e also is greater than c. If, however, the Hubble constant decreases enough between times t_e and t, then B's recession speed at time t can be less than c. If this is the case, then at time t (and spatial position B), the pulse is moving towards us, i.e., the pulse "turned around" at some time between times t_e and t.
If the value of the Hubble constant changes with time, what does the "constant" part of "Hubble constant" mean? It means constant in space. At time t_e, galaxies O, B, A, and C all perceive the same value for the Hubble constant. At time t, galaxies O, B, A, and C all perceive the same value for the Hubble constant. But these two values are different.
Probably some of my explanation is unclear. If so, please ask more questions.
Cosmo Novice said:This assumes that for galaxies whose recession>c for their photons to reach us then there must be a decrease in the Hubble constant. I thought the Hubble constant was the rate of acceleration of expansion and as such would always increase? I understand the constant referes to spatially constant (any given point in space will be the same constant as any other place at the same time) but am unclear whether this is increasing/decreasing.
George Jones said:The definition of the Hubble constant H is
H = \frac{\mbox{rate at which scale increases}}{\mbox{scale of the universe}}.
The universe expands with time, so the scale of the universe increases with time. Accelerated expansion means that the rate at which the scale increases itself increases, i.e., the rate tomorrow at which the scale increases is greater than rate today at which the scale increases. If, over a given period of time, the increase in the scale of the universe is proportionately greater than the increase in the rate at which the scale increases, then the Hubble constant decreases with time (since the denominator increases faster than the numerator. Observations indicate that this true now, and that this will remain true in the future.
I might later post a specific example.
Chronos said:Only to the extent necessary for the universe to be sufficiently large and ancient to permit our existence at this point in its history. Our efforts to measure scale factors is motivated by curiosity about the origins and destiny of the universe, not anthropic principles.
If the universe is spatially infinite, then yes.Cosmo Novice said:I guess the core question I am posing is: Beyond our OU, is there a cutoff point, in terms off recession speeds>c where we will no longer receive photons from galaxies further out than this cutoff point?
The universe doesn't have a boundary. The observable universe has a boundary. The laws of physics don't break down at the boundary of the observable universe. The boundary of the observable universe is not a place with special physical properties. It's simply the set of all points from which light has just barely had time to reach our own planet since the Big Bang. Tomorrow, that boundary will be about 3 light-days farther from us than it is today, so a certain volume of space will have become newly available to us for observation.Lost in Space said:But if the laws of physics break down at the boundaries, aren't these scale factors merely reduced to a human perspective and, given that, are they any closer to describing reality or are they merely a reflection on what we consider important in relation to ourselves?
bcrowell said:If the universe is spatially infinite, then yes.
The universe doesn't have a boundary. The observable universe has a boundary. The laws of physics don't break down at the boundary of the observable universe. The boundary of the observable universe is not a place with special physical properties. It's simply the set of all points from which light has just barely had time to reach our own planet since the Big Bang. Tomorrow, that boundary will be about 3 light-days farther from us than it is today, so a certain volume of space will have become newly available to us for observation.
BTW, we have a new entry on this topic in the cosmology forum's sticky FAQ thread.
Fortnum said:Since the Big Bang took place a finite time ago, the Universe would have had to expand at an infinite rate to reach an infinite size. Unless it was already infinite at the time of the Big Bang.
bcrowell said:If the universe is spatially infinite, then yes.
i don't think that universe is infinite. logic behind this is: as we know that infinite is not a real number. that means infinite is not reality. it is our imagination. the thing which cannot be counted we refer it as INFINITE. something imaginary, not real or uncountable. but that do not means that the universe is infinite. the thing is that we are not able enough to explore it and define the size of it...RuroumiKenshin said:I can't agree with you more, Mentat. I would say, maybe, that the universe is on the verge of infinity?[?]
I didn't quite get that right. For a closed universe with zero cosmological constant, you get a recollapse, so nothing is ever permanently hidden from any observer. But we know that the cosmological constant isn't zero, and recollapse is ruled out.Cosmo Novice said:I would suggest that even if U was spatially finite then it would probably be large enough for their to be photon emitting objects so far away that the expansion and scale factor of the intervening space would result in the photon never reaching us.
These are all different cases. The Big Bang is a physical singularity (not just a coordinate singularity). The event horizons of black holes are not physical singularities. The boundary between past and present isn't a uniquely defined thing in relativity. I thought you were talking about the boundary of the observable universe, which is still another thing.Lost in Space said:Pardon my confusion, but I've been given to understand that the Big Bang is a boundary where the laws of physics break down? What about event horizons of black holes? And isn't the present an ever moving and growing boundary as well as we cannot view future events, only events in the past?
thekushal276 said:i don't think that universe is infinite. logic behind this is: as we know that infinite is not a real number. that means infinite is not reality. it is our imagination. the thing which cannot be counted we refer it as INFINITE. something imaginary, not real or uncountable. but that do not means that the universe is infinite. the thing is that we are not able enough to explore it and define the size of it...
bcrowell said:These are all different cases. The Big Bang is a physical singularity (not just a coordinate singularity). The event horizons of black holes are not physical singularities. The boundary between past and present isn't a uniquely defined thing in relativity. I thought you were talking about the boundary of the observable universe, which is still another thing.
Lost in Space said:But aren't black holes physical singularities bounded by event horizons? And they're part of the observable universe are they not?
bcrowell said:The physical (non-coordinate) singularity is at the black hole's center, not at its event horizon.
Shenstar said:I find an infinite universe impossible to comprehend.
Lost in Space said:Yes, I understand this much but surely the boundary of the black hole is its event horizon which separates us from it? Although we cannot observe the singularity at the black hole's centre, we are still aware that it's there, so isn't the event horizon in this case a boundary within the observable universe?
Lost in Space said:Pardon my confusion, but I've been given to understand that the Big Bang is a boundary where the laws of physics break down? What about event horizons of black holes? And isn't the present an ever moving and growing boundary as well as we cannot view future events, only events in the past?
That doesn't make an infinite big bang a physical possibility, though. The only way the universe could be infinite is if it never had a beginning, ie that its beginning was an infinite time ago. Not plausible.narrator said:I find it difficult but not impossible. We live our lives by many paradigms and when confronted with one that's different we think "contradiction" or even "contravention".
DavidMcC said:That doesn't make an infinite big bang a physical possibility, though. The only way the universe could be infinite is if it never had a beginning, ie that its beginning was an infinite time ago. Not plausible.
You may have to re-invent physics for that, Cosmo!Cosmo Novice said:I don't think this is necessarily true, as I understand it something does not require infinite age to be spatially infinite. If the U is infinite now, then essentially it was infinite at the moment of the BB, so you could say if the U is open and spatially flat it is temporally finite but spatially infinite.
DavidMcC said:You may have to re-invent physics for that, Cosmo!
Cosmo Novice said:I don't think this is necessarily true, as I understand it something does not require infinite age to be spatially infinite. If the U is infinite now, then essentially it was infinite at the moment of the BB, so you could say if the U is open and spatially flat it is temporally finite but spatially infinite.
Cosmo Novice is correct. Standard spatially flat models of the universe are spatially infinite but have only existed for a finite time.DavidMcC said:You may have to re-invent physics for that, Cosmo!Cosmo Novice said:I don't think this is necessarily true, as I understand it something does not require infinite age to be spatially infinite. If the U is infinite now, then essentially it was infinite at the moment of the BB, so you could say if the U is open and spatially flat it is temporally finite but spatially infinite.
This is incorrect. Here is a good explanation: http://www.astro.ucla.edu/~wright/cosmology_faq.html#XINNeandethal00 said:If the U is really expanding, it is expanding into another region
bcrowell said:Cosmo Novice is correct. Standard spatially flat models of the universe are spatially infinite but have only existed for a finite time.
This is incorrect. Here is a good explanation: http://www.astro.ucla.edu/~wright/cosmology_faq.html#XIN
narrator said:As a simplistic example, under the right conditions, a fog appears everywhere with no starting point. Sure, the analogy breaks down if you get into the nitty gritty, but to me, it's a very rough analog of how the universe formed - one difference being that the "right conditions" were not localized.
bcrowell said:Cosmo Novice is correct. Standard spatially flat models of the universe are spatially infinite but have only existed for a finite time.
This is incorrect. Here is a good explanation: http://www.astro.ucla.edu/~wright/cosmology_faq.html#XIN
DavidMcC said:You (and UCLA) are making the same mistake as George (IMO), in equating black holes to the classical theory of them, which does not allow for an LQG BH, in which it is a mass quantum effect (just like superfluids and supeconductors, etc).
Also, flatness cannot be measured to zero error, so a large, but finite, curvature is necessarily a possibility, no matter how accurate the measurement.
Cosmological solutions with negative spatial curvature are also spatially infinite but have existed for a finite time. You simply have an issue about cosmology that you don't understand properly, as in this quote:DavidMcC said:Also, flatness cannot be measured to zero error, so a large, but finite, curvature is necessarily a possibility, no matter how accurate the measurement.
That doesn't make an infinite big bang a physical possibility, though. The only way the universe could be infinite is if it never had a beginning, ie that its beginning was an infinite time ago. Not plausible.
The text you quoted wasn't about black holes.DavidMcC said:You (and UCLA) are making the same mistake as George (IMO), in equating black holes to the classical theory of them, which does not allow for an LQG BH, in which it is a mass quantum effect (just like superfluids and supeconductors, etc).
apeiron said:This is definitely an alternative way of viewing the issue. As a phase transition. Time and space as something definite would have been born out of something far less definite. You could call it a fog, a vagueness, a pre-geometry, a perfect symmetry.
DavidMcC said:You may have to re-invent physics for that, Cosmo!