George Jones
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I know this is very counter-intuitive, but I really did mean what I wrote in posts #52 and #55.
Thanks for pushing me for further explanation, as this has forced me to think more conceptually about what happens.
This can happen because the Hubble constant decreases with time (more on this near the end of this post) in the standard cosmological model for our universe. Consider the following diagram:
The bottom row of asterisks represents the positions in space (proper distances) of us (O) and galaxies B, A, and C, all at the same instant of cosmic time, [itex]t_e[/itex]. The top row of asterisks represents the positions in space of us (O) and galaxies B, A, and C, all at some later instant of cosmic time, [itex]t[/itex]. Notice that space has "expanded" between times [itex]t_e[/itex] and [itex]t[/itex].
Suppose that at time [itex]t_e[/itex]: 1) galaxy A has recession speed (from us) greater than c; 2) galaxy A fires a laser pulse directed at us. Also suppose that at time [itex]t[/itex], galaxy B receives this laser pulse. In other words, the pulse was emitted from A in the bottom row and received by B in the top row. Because A's recession speed at time [itex]t_e[/itex] is greater than c, the pulse fired towards us has actually moved away from us between times [itex]t_e[/itex] and [itex]t[/itex].
Now, suppose that the distance from us to galaxy B at time [itex]t[/itex] is the same as the distance to galaxy C at time [itex]t_e[/itex]. Even though the distances are the same, the recession speed of B at time [itex]t[/itex] is less than than the recession speed of C at time [itex]t_e[/itex] because:
1) recession speed equals the Hubble constant multiplied by distance;
2) the value of the Hubble constant decreases between times [itex]t_e[/itex] and [itex]t[/itex].
Since A's recession speed at time [itex]t_e[/itex] is greater than c, and galaxy C is farther than A, galaxy C's recession speed at time [itex]t_e[/itex] also is greater than c. If, however, the Hubble constant decreases enough between times [itex]t_e[/itex] and [itex]t[/itex], then B's recession speed at time [itex]t[/itex] can be less than c. If this is the case, then at time [itex]t[/itex] (and spatial position B), the pulse is moving towards us, i.e., the pulse "turned around" at some time between times [itex]t_e[/itex] and [itex]t[/itex].
If the value of the Hubble constant changes with time, what does the "constant" part of "Hubble constant" mean? It means constant in space. At time [itex]t_e[/itex], galaxies O, B, A, and C all perceive the same value for the Hubble constant. At time [itex]t[/itex], galaxies O, B, A, and C all perceive the same value for the Hubble constant. But these two values are different.
Probably some of my explanation is unclear. If so, please ask more questions.
Cosmo Novice said:How will it "turn around" Can you please clarify this point.
Thanks for pushing me for further explanation, as this has forced me to think more conceptually about what happens.
This can happen because the Hubble constant decreases with time (more on this near the end of this post) in the standard cosmological model for our universe. Consider the following diagram:
Code:
O B A C
* * * ** * * *
O B A C
The bottom row of asterisks represents the positions in space (proper distances) of us (O) and galaxies B, A, and C, all at the same instant of cosmic time, [itex]t_e[/itex]. The top row of asterisks represents the positions in space of us (O) and galaxies B, A, and C, all at some later instant of cosmic time, [itex]t[/itex]. Notice that space has "expanded" between times [itex]t_e[/itex] and [itex]t[/itex].
Suppose that at time [itex]t_e[/itex]: 1) galaxy A has recession speed (from us) greater than c; 2) galaxy A fires a laser pulse directed at us. Also suppose that at time [itex]t[/itex], galaxy B receives this laser pulse. In other words, the pulse was emitted from A in the bottom row and received by B in the top row. Because A's recession speed at time [itex]t_e[/itex] is greater than c, the pulse fired towards us has actually moved away from us between times [itex]t_e[/itex] and [itex]t[/itex].
Now, suppose that the distance from us to galaxy B at time [itex]t[/itex] is the same as the distance to galaxy C at time [itex]t_e[/itex]. Even though the distances are the same, the recession speed of B at time [itex]t[/itex] is less than than the recession speed of C at time [itex]t_e[/itex] because:
1) recession speed equals the Hubble constant multiplied by distance;
2) the value of the Hubble constant decreases between times [itex]t_e[/itex] and [itex]t[/itex].
Since A's recession speed at time [itex]t_e[/itex] is greater than c, and galaxy C is farther than A, galaxy C's recession speed at time [itex]t_e[/itex] also is greater than c. If, however, the Hubble constant decreases enough between times [itex]t_e[/itex] and [itex]t[/itex], then B's recession speed at time [itex]t[/itex] can be less than c. If this is the case, then at time [itex]t[/itex] (and spatial position B), the pulse is moving towards us, i.e., the pulse "turned around" at some time between times [itex]t_e[/itex] and [itex]t[/itex].
If the value of the Hubble constant changes with time, what does the "constant" part of "Hubble constant" mean? It means constant in space. At time [itex]t_e[/itex], galaxies O, B, A, and C all perceive the same value for the Hubble constant. At time [itex]t[/itex], galaxies O, B, A, and C all perceive the same value for the Hubble constant. But these two values are different.
Probably some of my explanation is unclear. If so, please ask more questions.
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