The velocity of a moving frame of reference

In summary, the conversation discusses an experiment involving a moving frame of reference (MFR) and two identical train carriages, one of which can move while the other cannot. The experiment also involves two identical clocks attached to the train tracks, and a light tube inside one of the train carriages. When an electric pulse is sent down the wire from the light tube, it makes a mark on the train track, allowing the position of the train at the time the pulse was sent to be known. The time it takes for light to traverse the length of the light tube is measured by the clocks, and the velocity and direction of the MFR can be calculated based on this. However, there are some errors with the analysis of the experiment,
  • #36
"the point is only a point in one frame"

a strobe goes off and photons emanate from that point in straight lines in all directions

the speed of photons is invariant in all frames

if in 1 million yrs time I meticulously traced those photons back along their trajectories to the point from which they emanated. is that an arbitrary point ?
 
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  • #37
for me to be wrong would be a breach of the laws of physics
 
  • #38
RossBlenkinsop said:
is that an arbitrary point ?
Yes. It depends which frame you use what that point is. Janus' two diagrams demonstrate this clearly. But it should be obvious.

Work in a frame where the light source is at rest. It emits a spherical wavefront. Backtrace the rays and you get to the light source.

Now work in a frame where the lightsource is moving. It emits a spherical wavefront. Backtrace the rays and you get to the place where the light source was, not where it is now. Thus this is a different point from the previous paragraph.
 
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  • #39
because the speed of light is invariant regardless of the elapsed time period elapsed tracing the trajectories of those photons will always lead back to the same point

its almost as if the point is at an absolute position in space
 
  • #40
Ibix said:
Yes. It depends which frame you use what that point is. Janus' two diagrams demonstrate this clearly. But it should be obvious.

Work in a frame where the light source is at rest. It emits a spherical wavefront. Backtrace the rays and you get to the light source.

Now work in a frame where the lightsource is moving. It emits a spherical wavefront. Backtrace the rays and you get to the place where the light source was, not where it is now. Thus this is a different point from the previous paragraph.

In both instances u retrace the photons trajectory to the point from which they emanated ! Just so happens in scenario 1 the actual light itself is at rest wrt the point x1 y1 ...your basically agreeing with me
 
  • #41
RossBlenkinsop said:
because the speed of light is invariant regardless of the elapsed time period elapsed tracing the trajectories of those photons will always lead back to the same point
You're clearly not even reading what I write, now. I just explained how this is not the case. Please re-read post #38 and say what you do not understand.

RossBlenkinsop said:
its almost as if the point is at an absolute position in space
This has been known to be meaningless for around three and a half centuries.
 
  • #42
its almost as if the point is at an absolute position in space

that point cannot move, if it did that would mean the speed of light is not invariant
 
  • #43
RossBlenkinsop said:
In both instances u retrace the photons trajectory to the point from which they emanated ! Just so happens in scenario 1 the actual light itself is at rest wrt the point x1 y1 ...your basically agreeing with me
I am not even slightly agreeing with you. You claim that the place where the light is and a place where it isn't are the same place. That is clearly nonsense.
 
  • #44
because the speed of light is invariant the 2 or more photons on the wave front must be exactly the same distance from the point X1 Y1 for all time

or in other words tracing back along the trajectories will always lead back to the same point, regardless of the frame used or the time period elapsed
 
  • #45
or in other words the location of that point remains the same over time
and I am pretty sure if the location of something remains the same over time then that is the definition of "not moving"
 
  • #46
RossBlenkinsop said:
point X1 Y1
Again, this point is only stationary in one frame. In other frames, this point is moving and does not remain at the centre of the pulse.
RossBlenkinsop said:
in other words tracing back along the trajectories will always lead back to the same point
...but different frames will not agree what this point is and will all regard all other frames' "same points" as changing position.
RossBlenkinsop said:
in other words the location of that point remains the same over time
...according to the frame used to do the backtracing. Every other frame will come up with a stationary point too. But the whole point of different frames of reference is that they don't agree with each other what "stationary" means. They all regard the others' "stationary points" as moving, so there is no "absolutely stationary".

Look. Say the pulse is emitted at the origin in some frame. After time ##t## the pulse is at ##x,y## coordinates that satisfy ##c^2t^2=x^2+y^2##. Always centred on ##x,y=0,0##.

In another frame, the pulse was also emitted at the origin. After time ##t'## the pulse is at ##x',y'## coordinates that satisfy ##c^2t'^2=x'^2+y'^2##. Always centred on ##x',y'=0,0##.

But what is the Lorentz transform of ##x,y=0,0##? It's ##x',y'=-\gamma vt,0##, which is a moving point. The frames do not agree on what "where the light was emitted" means, except at the instant it was emitted.

I don't think I can state it more clearly than that, and it's 1am here. Signing off.
 
  • #47
Ugh. Thought of a way that might be clearer to you.

You agree that the strobe light is moving in one frame and stationary in the other. Thus it is (to use your terminology) "at rest with respect to X1,Y1" in one frame and not the other. But one of your light clocks was stationary with respect to the strobe light while the other was stationary in the frame where the strobe light is moving. Thus, which clock is "at rest with respect to X1,Y1" is different in the two frames.

Therefore the two frames disagree which clock ticks fastest.

I've put scare quotes around "at rest with respect to X1,Y1" because it's horrible and potentially misleading notation. It can, however, be made rigorous by adding bouys at the relevant coordinates at rest in the relevant frames. Naturally, they are moving with respect to one another.

Now I'm really going to sleep.
 
  • #48
RossBlenkinsop said:
because the speed of light is invariant regardless of the elapsed time period elapsed tracing the trajectories of those photons will always lead back to the same point
That's just plain wrong, unless you are using the word "point" to mean a point in spacetime as opposed to a point in space (in which case we have more confusion from you using words differently than everyone else and should be using the word "event" because that's something completely different than a point in space).
or in other words the location of that point remains the same over time
and I am pretty sure if the location of something remains the same over time then that is the definition of "not moving"
No, the phrase "not moving" is completely meaningless unless you say what the the object in question is at rest relative to. And even then there's a lot to be said for being precise: "Using the coordinates assigned by a frame in which the spatial coordinates do not change...". This is some of what @Ibix was getting at in the post above when he said
I've put scare quotes around "at rest with respect to X1,Y1" because it's horrible and potentially misleading notation. It can, however, be made rigorous by adding bouys at the relevant coordinates at rest in the relevant frames. Naturally, they are moving with respect to one another.

If you can get hold of a copy of Taylor and Wheeler's book "Spacetime Physics", you will find it very helpful. An internet forum like this one is pretty good at pointing out errors and helping people over isolated hard spots, but not the best way of unwinding misunderstandings.
 
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  • #49
RossBlenkinsop said:
because the speed of light is invariant the 2 or more photons on the wave front must be exactly the same distance from the point X1 Y1 for all time

or in other words tracing back along the trajectories will always lead back to the same point, regardless of the frame used or the time period elapsed

You have three objects, A, B, and C in relative motion with respect to each other and all passing each other the same moment. As they pass each other, a light flash is emitted from them.
According to B, events unfold like this:
PULSE1.gif


However, according to C, events unfold like this:
PULSE2.gif


and according to A, they unfold like this:

PULSE3.gif


Each of them measures the light flash as expanding out away from themselves at c.

If, after the last frame of each of these animations, you were to ask each of them to "retrace the light pulse to its origin, they would trace it back to themselves. But A B and C have separated and in three different points in the last frame, and so they would not agree that the rays trace back to the same spot.
 
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  • #50
well there is an absolute fact

if the speed of light is indeed invariant, regardless of what anyone perceives in any frame, measures in any frame doesn't measure in any frame what ever

if a light strobes at a point X1 Y1 simple maths tells us that 3 photons in the wave front will always triangulate back to the same point in space, for all time or aka that point remains in the same location for all time

if they don't triangulate back to that point then that means the speed of light is not invariant

so which is it is the speed of light not invariant or do the photons triangulate to a set point in space ?
 
  • #51
there may be difficulty devising an experiment to measure where that point is but never the less
u can't have yr cake and eat it to
 
  • #52
RossBlenkinsop said:
if a light strobe at a point X1 Y1 simple maths tells us that 3 photons in the wave front will always triangulate back to the same point in space
Please state this maths. How is it different from what I laid out in #46, and which Janus presented diagramatically in #49? Remember to carry out the maths in two different frames and relate the locations in the two frames. If you do this correctly you will realize that "the same point in space" means different things to different frames. It is not an absolute.
RossBlenkinsop said:
the speed of light not invariant or do the photons triangulate to a set point in space ?
They "triangulate back" to different points according to different frames; the point one frame calls "stationary at the centre of the spherical pulse" other frames call "moving and not at the centre". I have stated this multiple times, both verbally and mathematically, and correct diagrams have been presented to you supporting this. That "a fixed point in space" is a frame-dependent notion, not an absolute one, dates back to Galileo and all of physics assumes the notion.
 
  • #53
can you explain how a single strobing light with invariant speed photon can triangulate back to multiple centre points ?
 
  • #54
RossBlenkinsop said:
can you explain how a single strobing light with invariant speed photon can triangulate back to multiple centre points ?
I already did. See post #46.
 
  • #55
so it is impossible to conclude that the speed of light is invariant then
ok
 
  • #56
RossBlenkinsop said:
so it is impossible to conclude that the speed of light is invariant then
ok
I used the invariance of ##c## in #46...
 
  • #57
I repeat: please state the "simple maths" that supports your assertion that there is an absolute frame-invariant point from which the light radiates. You claimed there was some in #50. I know, having done the maths myself and presented a sketch above, that this claim is wrong - so I want to see your maths. Obviously there's a mistake in it somewhere.
 
  • #58
so what you are saying is if there is a single strobing light that strobes only once and 100 different ppl in 100 different frames, they all agree there is only one light and that it strobed once ,

but 3 photons on that wave front will map back to 100 different points

so what should they conclude from the results of that experiment ?

they cannot conclude there was 100 lights cos they all saw one and they can only conclude it strobed once

they would have to conclude there was 1 light simultaneously in 100 different locations
ok
 
  • #59
or the other thing they could conclude is that there was one light at one location and there is something wrong with the ,measuring technique

Now

If they conclude there is one light at one location , then all roads lead to Rome
 
  • #60
RossBlenkinsop said:
so what should they conclude from the results of that experiment ?
Let's define your experiment better: one person is at rest with respect to the strobe. The other 99 are all in motion with respect to the first and to each other, and all pass the first person simultaneously. At the instant they pass him, he triggers the strobe. All one hundred people agree that the light flash happened at their location. Therefore when they subsequently back-trace the light rays they will always lead back to themselves because they each define themselves to be stationary. But they all agree that they are no longer in the same place. So they all disagree about what "where the flash happened" means.

There's nothing wrong with their measurement procedure. It's just ambiguous what "the same place" means, because there's no absolute standard of rest to define it. I don't really understand why you can't grasp this - it's been said enough times in enough different ways, and your own thought experiments lead to it if you analyse them correctly.

I'm still waiting for the "simple maths" that proves this wrong. It will never be forthcoming, of course, because there is no such thing.
 
  • #61
Also, a minor point, but you are required to write in proper English on this site, using capitals, punctuation, and actual words - "people" does not have three letters. Poor writing just makes it harder to understand an already complicated topic.
 
  • #62
Ibix said:
Let's define your experiment better

no let's not

lets say we have 100 000 people splattered everywhere in 100 000 different frames when the one light strobes once

now you have a single light in 100 000 different locations simultaneously
 
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  • #63
Same answer. They all say the light flash happened where they are. They all agree that the others are not where they are. Therefore they all disagree about what "where the flash happened" means at any time except when it happened.

Adding zeros doesn't change anything. You are simply wrong 100,000 times instead of 100 times.
 
  • #64
Ibix said:
I repeat: please state the "simple maths" that supports your assertion that there is an absolute frame-invariant point from which the light radiates.

so are you saying if there is a single strobe light in my lounge room that strobes once, and photons radiate out from the strobe in straight lines at a set speed

there are multiple center points to that wave front of photons ?

if that is the case the speed of light is not invariant as that is the only way those photons can map back to multiple points

I don't need simple math as your friends animation shows the photons radiate outwards in straight lines in all directions at an invariant speed from a central point... but apparently if time is reversed they map back to multiple points thus negating the entire assertion they are speed invariant
 
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  • #65
Why do you keep asking the same question? Do you think I'll change my mind if you ask it 23 times? Or 24?

Yes. Every frame has a different interpretation of what "centre point" means in this context. This is perfectly consistent with an invariant speed of light and I don't understand why you think otherwise.

I've already shown you the maths to support my claim (post #46 - note the presence of the same ##c## in both frames' calculations). Show me the maths you claim to have that says otherwise. Until you do so, you are simply waving your hands and refusing to believe that the world doesn't work like you think it ought to.
 
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  • #66
RossBlenkinsop said:
so which is it is the speed of light not invariant or do the photons triangulate to a set point in space ?
The speed of light is invariant and the light does not triangulate back to a set point in space.
It does triangulate back to the same point in spacetime (although the correct word for a point in spacetime is “event”, not “point”), the one at which the light was emitted.

You will continue to be confused until you understand the difference between a point in space and a point in spacetime. A point in space is a line (called a “worldline”) in spacetime; googling for “Minkowski diagram worldline” will bring up many explanations and examples.
 
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  • #67
Same answer. They all say the light flash happened where they are. They all agree that the others are not where they are. Therefore they all disagree about what "where the flash happened" means at any time except when it happened.

Adding zeros doesn't change anything. You are simply wrong 100,000 times instead of 100 times.

sorry i simply do not understand this reply
 
  • #68
RossBlenkinsop said:
sorry i simply do not understand this reply
He’s saying that if it makes sense for two observers moving relative to one another it will also make sense for ten, or a hundred, or 100,000... so you should focus on understanding the two-observer case.
 
  • #69
as explained before there is a train in a large building, 2 light clocks in the large building (LB) to, 1 in the train the other at rest wrt the building

the building and everything in it is whizzing thru space at some velocity V in some direction V

there is a strobe light in the roof

the train heads off along the tracks. Purely by chance the tracks are parallel to the direction of travel of the LB

The train heads off and attains a steady velocity. Purely by chance the velocity of the train is exactly the same as that of the LB , but in the opposite direction

we end up with the situation as depicted.

Purely by chance the strobe light in the roof strobes at the instant the train is directly below the light

once a photon enters a light tube it is reflected up and down

an observer in the frame will see the train whizzing away from them and the light clock in the train will be perceived by the observer to be ticking slower than the clock at rest wrt the observer

as before pulses are sent back along the train lines

will the train line pulses tick faster than the clock at rest wrt the observer

I have drawn the successive events one under another
 

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  • #70
RossBlenkinsop said:
can you tell me what is wrong with my logic
This picture shows the light propagating at speed ##c## using the frame in which the railcar is at rest, but not using the frame in which the strobe light and other stuff is at rest. Take another careful look at post #29 of this thread by @Janus and also try drawing a Minkowski diagram instead of trying to represent the passage of time as a series of still pictures.

I also think that you may be overlooking the relativity of simultaneity here. That’s another good google search.
 
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<h2>1. What is a moving frame of reference?</h2><p>A moving frame of reference is a coordinate system used to describe the motion of an object or system. It is a relative measurement, meaning it depends on the observer's perspective.</p><h2>2. How is the velocity of a moving frame of reference calculated?</h2><p>The velocity of a moving frame of reference is calculated by dividing the change in position by the change in time. This is known as the average velocity and is represented by the equation v = Δx/Δt.</p><h2>3. What is the difference between velocity and speed?</h2><p>Velocity is a vector quantity that describes both the speed and direction of an object's motion. Speed, on the other hand, is a scalar quantity that only describes the rate of motion without considering direction.</p><h2>4. Can the velocity of a moving frame of reference be negative?</h2><p>Yes, the velocity of a moving frame of reference can be negative. This indicates that the object is moving in the opposite direction of the chosen frame of reference.</p><h2>5. How does the velocity of a moving frame of reference affect measurements?</h2><p>The velocity of a moving frame of reference affects measurements by introducing the concept of relativity. This means that the measurements taken by an observer in one frame of reference may differ from those taken by an observer in a different frame of reference.</p>

1. What is a moving frame of reference?

A moving frame of reference is a coordinate system used to describe the motion of an object or system. It is a relative measurement, meaning it depends on the observer's perspective.

2. How is the velocity of a moving frame of reference calculated?

The velocity of a moving frame of reference is calculated by dividing the change in position by the change in time. This is known as the average velocity and is represented by the equation v = Δx/Δt.

3. What is the difference between velocity and speed?

Velocity is a vector quantity that describes both the speed and direction of an object's motion. Speed, on the other hand, is a scalar quantity that only describes the rate of motion without considering direction.

4. Can the velocity of a moving frame of reference be negative?

Yes, the velocity of a moving frame of reference can be negative. This indicates that the object is moving in the opposite direction of the chosen frame of reference.

5. How does the velocity of a moving frame of reference affect measurements?

The velocity of a moving frame of reference affects measurements by introducing the concept of relativity. This means that the measurements taken by an observer in one frame of reference may differ from those taken by an observer in a different frame of reference.

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