The velocity of the particle as a function of time

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SUMMARY

The discussion focuses on determining the velocity of a particle as a function of time, given the acceleration equation a(t) = bt y + c e^(kt) z. The initial conditions specify that at t=0, the velocity is v(0) = d x + (c/k) z and the position is r(0) = (c/k^2) z. A participant questions the correct form of the velocity equation, suggesting it should be (c/k) * exp(kt) without the exponent notation. The relevant equation for velocity is v(t) = ∫ a(t) dt.

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yesmale4
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Homework Statement
The acceleration of the particle is given by a(t)=bt y + c e kt z.
It is known that at t=0 the velocity of the particle is by v(0)= d x + c/k z and its position is r(0)= c/k2 z.
b, c, d and k are constants.
Relevant Equations
v\left(t\right)=\int \:a\left(t\right)dt
sa.png

this is how i try to solve it:
mm.jpeg


can someone please help me with that because i don't know what I am doing worng here.
 

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Isn't the problem that it should be
Code:
(c/k)*exp(k*t)
(without the ^)?
 
DrClaude said:
Isn't the problem that it should be
Code:
(c/k)*exp(k*t)
(without the ^)?
Thank you very much !
 
yesmale4 said:
Homework Statement:: The acceleration of the particle is given by a(t)=bt y + c e kt z.
It is known that at t=0 the velocity of the particle is by v(0)= d x + c/k z and its position is r(0)= c/k2 z.
b, c, d and k are constants.
Relevant Equations:: v\left(t\right)=\int \:a\left(t\right)dt

View attachment 297864
this is how i try to solve it:
View attachment 297866

can someone please help me with that because i don't know what I am doing wrong here.
Is it telling you it is wrong or is that just what you think?
 

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