The Work Done in Pulling a Supertanker

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SUMMARY

In the discussion, participants analyze the physics problem involving two tugboats pulling a disabled supertanker with a force of 1.90×106 N at angles of 13.0 degrees west and east of north. The correct calculation for the work done is confirmed to be 3.11E+9 J, highlighting the importance of using degrees instead of radians in calculations. A rounding error was identified in the initial attempt, which resulted in an incorrect value of 2.9E+9 J. The discussion emphasizes the need for precise input in calculations, especially when using calculators that default to radians.

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  • Experience with scientific notation and calculations involving large numbers
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Homework Statement



Two tugboats pull a disabled supertanker. Each tug exerts a constant force of 1.90×10^6 N , one at an angle 13.0 degrees west of north, and the other at an angle 13.0 degrees east of north, as they pull the tanker a distance 0.840 km toward the north.

Homework Equations





The Attempt at a Solution



2 * (1.90×10^6 N) * cos(13) * 0.84 * 10^3 = 2.9 * 10 ^9

can anyone tell me where I did a mistake?

Thanks a lot before hand
 
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It does not look like you made a mistake.
 
rock_star said:

Homework Statement



Two tugboats pull a disabled supertanker. Each tug exerts a constant force of 1.90×10^6 N , one at an angle 13.0 degrees west of north, and the other at an angle 13.0 degrees east of north, as they pull the tanker a distance 0.840 km toward the north.


The Attempt at a Solution

Solution to what?
 
rock.freak667 said:
It does not look like you made a mistake.

It is showed that I made a mistake :(
Rounding error..
It is 3.11 not 2.9 :(

Thanks a lot though! :)
 
Last edited:
The correct answer is 3.11E+9. Make sure you use 13 DEGREES and not 13 RADIANS. If you entered into a *dumb* calculator, it usually assumes radians. Try writing

2*1.9E6*cos(13*pi/180)*0.84E3 into google, and it gives you the right answer.
 

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