Theorem mathematic for relativity

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Discussion Overview

The discussion revolves around a mathematical theorem related to the representation of functions and its application in the context of relativity. Participants explore the formulation of the theorem, its proof, and its implications for changes in coordinates within Einstein's equations and the geometry of space-time.

Discussion Character

  • Technical explanation
  • Mathematical reasoning
  • Debate/contested

Main Points Raised

  • One participant presents a theorem involving a function F and its representation using a sum and derivatives, seeking guidance on how to derive the sum from a fundamental theorem of calculus.
  • Another participant references the standard Taylor series and suggests that the notation used by the original poster may be incorrect, specifically regarding the terms in the sum.
  • A third participant provides a formal statement of a related theorem, mentioning the existence of smooth functions H that relate to the derivatives of F, and suggests a reference for further study.
  • Clarifications are made regarding notation, with emphasis on ensuring clarity in mathematical expressions to avoid confusion.
  • A later reply includes a proof of the theorem, detailing the steps taken and defining the function H in terms of integrals of partial derivatives.

Areas of Agreement / Disagreement

Participants express differing views on the notation and formulation of the theorem, indicating a lack of consensus on the initial representation. While some agree on the validity of the theorem's application, others challenge the clarity and correctness of the notation used.

Contextual Notes

There are unresolved issues regarding the notation and assumptions underlying the theorem, which may affect the clarity of the discussion. The dependence on specific definitions and the context of the theorem's application in relativity are also noted.

nulliusinverb
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hello!:

my problem is about of a theorem mathematic,as I prove the following theorem?

F(x)=F(a) + [itex]\sum^{n}_{i=1}[/itex](x[itex]^{i}[/itex]-a[itex]^{i}[/itex])H[itex]_{i}[/itex](x)

good first start with the fundamental theorem of calculus: (for proof):

F(x) - F(a) = [itex]\int^{x}_{a}[/itex]F'(s)ds sustitution: s=t(x - a) + a [itex]\Rightarrow[/itex] [a,x] to [0,1] then:
ds=dt(x - a) later:
f(x) - F(a)= (x - a)[itex]\int^{1}_{0}[/itex]F'(t(x - a) +a)dt

okk my problem is how to get to the sum [itex]\sum[/itex]?

is physics relativistic forum, because of this theorem I can get to the change of coordinates in the Einstein equations and find bases for the manifolds of space-time. thanks!
 
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http://en.wikipedia.org/wiki/Taylor_series

Your representation is a modification of the standard Taylor series representation, where Hi(a) (not Hi(x)) is related to the ith derivative of F.

Furthermore the term in parenthesis should be (x-a)i not xi - ai
 
mathman said:
Furthermore the term in parenthesis should be (x-a)i not xi - ai
I know it's not clear from what he said, but he has a different theorem in mind. Wald's statement of the theorem goes like this:
If ##F:\mathbb R^n\to\mathbb R## is ##C^\infty##, then for each ##a=(a^1,\dots,a^n)\in\mathbb R^n## there exist ##C^\infty## functions ##H_\mu## such that for all ##x\in\mathbb R^n## we have
$$F(x)=F(a)+\sum_{\mu=1}^n(x^\mu-a^\mu)H_\mu(x).$$ Furthermore, we have
$$H_\mu(a)=\frac{\partial F}{\partial x^\mu}\bigg|_{x=a}.$$​
A similar theorem is stated and proved in Isham's book on differential geometry, page 82. So nulliusinverb, I suggest you take a look at that.
 
Fredrick thank you very much, the book is recommended to study this issue, although the theorem is raised from other values ​​is the same. thank!

ps: "Modern Differential Geometry for Physicists" autor: Isham
 
Notation is a major problem here. xi usually means the ith power of x. For this theorem it means the ith component of a vector x ε Rn.

I suggest that, when anyone asks a question, make sure the notation is clear!
 
i apologize for the delay, here is the proof:

F:ℝ[itex]^{n}[/itex][itex]\rightarrow[/itex]ℝ

i have:

F([itex]\vec{x}[/itex])-F([itex]\vec{a}[/itex])= [itex]\sum[/itex][itex]^{m}_{μ=1}[/itex]F(t(x[itex]^{μ}[/itex]-a[itex]^{μ}[/itex])+a[itex]^{μ}[/itex],0...,0)[itex]^{t=1}_{t=0}[/itex]
then:
=[itex]\sum[/itex][itex]^{m}_{μ=1}[/itex](x[itex]^{μ}[/itex]-a[itex]^{μ}[/itex])[itex]\int[/itex][itex]^{1}_{0}[/itex][itex]\frac{\partial F}{\partial u^{μ}}[/itex]((t(x[itex]^{μ}[/itex]-a[itex]^{μ}[/itex])+a[itex]^{μ}[/itex],0...,0)dt
where:

H[itex]_{μ}[/itex]([itex]\vec{x}[/itex])=[itex]\int[/itex][itex]^{1}_{0}[/itex][itex]\frac{\partial F(\vec{x})}{\partial u^{μ}}[/itex]dt

finally:

F([itex]\vec{x}[/itex])-F([itex]\vec{a}[/itex])= [itex]\sum[/itex][itex]^{m}_{μ=1}[/itex]H[itex]_{μ}[/itex]([itex]\vec{x}[/itex])(x[itex]^{μ}[/itex]-a[itex]^{μ}[/itex])

qed

thanks you very much to all!
 

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