Thermal Efficiency in an Ideal Diesel cycle.

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SUMMARY

The thermal efficiency of an ideal Diesel cycle using helium is calculated using the formula $$\eta_{TH}=1-\frac{1}{r^{k-1}}[\frac{r_c^k-1}{k(r_c-1)}]$$. The compression ratio \( r_c \) is determined to be 2, and the overall compression ratio \( r \) is 16. Using the specific heat ratio \( k \) for helium, which is 1.667, the thermal efficiency is 79.5%. In contrast, using the specific heat ratio for air (1.4) yields a thermal efficiency of 61.4%.

PREREQUISITES
  • Understanding of the Diesel cycle and its processes
  • Familiarity with specific heat ratios (gamma) for different gases
  • Knowledge of thermodynamic efficiency calculations
  • Basic principles of adiabatic and isothermal processes
NEXT STEPS
  • Research the specific heat ratios of various gases, focusing on helium and air
  • Study the principles of the Diesel cycle in detail, including its phases
  • Explore thermodynamic efficiency calculations in different cycles
  • Investigate the practical applications of helium in thermodynamic cycles
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Students studying thermodynamics, engineers working with Diesel engines, and anyone interested in the application of different gases in thermodynamic cycles.

MacLaddy
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Homework Statement



Helium in an ideal Diesel cycle is compressed from 4 L to 0.25 L, and then it expands during the constant pressure heat addition process to 0.50 L. Under air standard conditions, the thermal efficiency of this cycle is:

a) 79.5%
b) 20.5%
c) 61.4%
d) 67.4%
e) 84.3%

Homework Equations



$$\eta_{TH}=1-\frac{1}{r^{k-1}}[\frac{r_c^k-1}{k(r_c-1)}]$$
$$r_c = \frac{v_3}{v_2}=\frac{0.50L}{0.25L}=2$$
$$r=\frac{v_1}{v_2}=\frac{4}{0.25}=16$$

The Attempt at a Solution



My main problem with this question is in the wording. "Under air standard conditions" I typically would use the k value of 1.4, but as it specifically states "Helium" I wonder if I shouldn't use k=1.667.

k=1.667 my answer is 79.5%
k=1.4 my answer is 61.4%

Any help on what the standard operation with this type of wording is would be greatly appreciated.

Thanks,
Mac
 
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I am not sure how helium works in a Diesel engine. But you aren't supposed to worry about that.

I suggest that you just assume that the system consists of only He connnected to hot and cold reservoirs. The cycle is comprised of a constant pressure expansion while connected to the hot reservoir, then an adiabatic expansion, then a constant volume cooling when connected to the cold reservoir, followed by adiabatic compression. Use the efficiency formula for the Diesel using the gamma for He.

AM
 
Andrew Mason said:
I am not sure how helium works in a Diesel engine. But you aren't supposed to worry about that.

I suggest that you just assume that the system consists of only He connnected to hot and cold reservoirs. The cycle is comprised of a constant pressure expansion while connected to the hot reservoir, then an adiabatic expansion, then a constant volume cooling when connected to the cold reservoir, followed by adiabatic compression. Use the efficiency formula for the Diesel using the gamma for He.

AM

Thank you, the gamma was based on Helium. Now I'm going to go build a Diesel Engine that runs on helium... (who writes this stuff?)

Mac
 

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