Thermal Energy in 1 cubic meter of air at room temperature

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SUMMARY

The thermal energy in 1 cubic meter of air at room temperature (25°C or 293.15 K) is calculated using the formula for the kinetic energy of gas molecules, resulting in approximately 151,815 Joules. The kinetic energy of the same volume of air falling from a height of 100 meters is determined using the gravitational potential energy formula, yielding 1,176 Joules. Therefore, the thermal energy significantly exceeds the gravitational energy in this scenario. The density of air at room temperature is approximately 1.2 kg/m³.

PREREQUISITES
  • Understanding of kinetic energy calculations using the formula 3/2 kT
  • Knowledge of gravitational potential energy calculations (PE = mgh)
  • Familiarity with the concept of molecular density in gases
  • Basic understanding of temperature scales (Celsius and Kelvin)
NEXT STEPS
  • Research the ideal gas law and its applications in thermodynamics
  • Learn about the properties of air and its behavior under different temperatures and pressures
  • Explore advanced kinetic theory of gases and its implications in physics
  • Study the relationship between thermal energy and temperature in various states of matter
USEFUL FOR

Students studying physics, particularly those focusing on thermodynamics and kinetic theory, as well as educators looking for practical examples of energy calculations in gases.

Bgerst103
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Homework Statement



How much thermal energy was in 1 cubic meter of air at room temperature. Give your answer in Joules.

How much kinetic energy does one cubic meter of air have if it were to hit the ground after falling 100 m? Give your answer in Joules.

Which has more energy? Gravitational energy or thermal energy?

Homework Equations





The Attempt at a Solution



I'm not really sure how to calculate thermal energy of air. Room temperature is 25C I believe.
 
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Perhaps think about the kinetic energy of a single gas molecule (=3/2 kT).
 
CWatters said:
Perhaps think about the kinetic energy of a single gas molecule (=3/2 kT).

So, there are about 2.5 x 10^25 molecules in 1m3 of air. K is 1.381 x 10^-23. I've decided to use 293.15 K as my temperature. So the kinetic energy of one molecule is 6.0726 x 10^-21. So do I multiply this by 2.5 x 10^25? That would come out to 151815. If this is right how would I turn this into joules?
 
If that's the right number of molecules (I haven't checked) then that would be the energy in Joules.
 
Thermal energy in one cubic meter of air

Homework Statement



How much thermal energy was in 1 cubic meter of air at room temperature. Give your answer in Joules.

How much kinetic energy does one cubic meter of air have if it were to hit the ground after falling 100 m? Give your answer in Joules.

Which has more energy? Gravitational energy or thermal energy?

Homework Equations



2/3kT

The Attempt at a Solution



So, there are about 2.5 x 10^25 molecules in 1m3 of air. K is 1.381 x 10^-23. I've decided to use 293.15 K as my temperature. The kinetic energy of one molecule is 6.0726 x 10^-21. So, I multiplied by 2.5 x 10^25 would come out to 151815 J, is this thermal energy? How do i calculate the kinetic energy after falling 100m? I'm assuming i just compare the two to answer the third question.
 
I think your calculation of the thermal energy is correct. Can you calculate the mass of 1 m^3 of air? Do you know how to calculate the gravitational potential energy gained when a mass m falls a distance h under the influence of gravity?
 
Bgerst103 said:
So, there are about 2.5 x 10^25 molecules in 1m3 of air. K is 1.381 x 10^-23. I've decided to use 293.15 K as my temperature. So the kinetic energy of one molecule is 6.0726 x 10^-21. So do I multiply this by 2.5 x 10^25? That would come out to 151815. If this is right how would I turn this into joules?

That's already in Joules (You would know that if you kept better track of units. That's a very important point that for some reason most student blow off as unimportant or trivial. Don't make that mistake. Instead of "K is 1.381 x 10^-23" say "kB = 1.381 x 10-23 J/K" Note all the changes I've made to your statement. They were all intentional). I didn't check your math, it but seems to be in the right ball park.
 
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phyzguy said:
I think your calculation of the thermal energy is correct. Can you calculate the mass of 1 m^3 of air? Do you know how to calculate the gravitational potential energy gained when a mass m falls a distance h under the influence of gravity?

The density of air at room temp is about 1.2 kg/m3 so mass would be M=DV so I guess the mass is just 1.2 as well? Gravitional potential energy is just PE=mgh correct? So then, 1.2(9.8)(100)=1176 meaning thermal energy is much greater than gravitational.
 
Bgerst103 said:
The density of air at room temp is about 1.2 kg/m3 so mass would be M=DV so I guess the mass is just 1.2 as well? Gravitional potential energy is just PE=mgh correct? So then, 1.2(9.8)(100)=1176 meaning thermal energy is much greater than gravitational.

I think that's correct.
 

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