Thermal Energy in 1 cubic meter of air at room temperature

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Homework Help Overview

The discussion revolves around calculating the thermal energy in one cubic meter of air at room temperature, as well as the kinetic energy of that air if it were to fall from a height of 100 meters. Participants are exploring the relationship between thermal energy and gravitational energy.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the calculation of thermal energy using the kinetic energy of gas molecules, referencing the formula for kinetic energy and the number of molecules in a cubic meter of air. Questions arise about the correctness of calculations and unit tracking.

Discussion Status

Some participants express confidence in their calculations of thermal energy, while others seek clarification on how to compute gravitational potential energy. There is an ongoing exploration of the relationship between thermal and gravitational energy, with various interpretations being considered.

Contextual Notes

Participants note the density of air at room temperature and its implications for mass calculations. There is an emphasis on ensuring correct unit usage throughout the discussion.

Bgerst103
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Homework Statement



How much thermal energy was in 1 cubic meter of air at room temperature. Give your answer in Joules.

How much kinetic energy does one cubic meter of air have if it were to hit the ground after falling 100 m? Give your answer in Joules.

Which has more energy? Gravitational energy or thermal energy?

Homework Equations





The Attempt at a Solution



I'm not really sure how to calculate thermal energy of air. Room temperature is 25C I believe.
 
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Perhaps think about the kinetic energy of a single gas molecule (=3/2 kT).
 
CWatters said:
Perhaps think about the kinetic energy of a single gas molecule (=3/2 kT).

So, there are about 2.5 x 10^25 molecules in 1m3 of air. K is 1.381 x 10^-23. I've decided to use 293.15 K as my temperature. So the kinetic energy of one molecule is 6.0726 x 10^-21. So do I multiply this by 2.5 x 10^25? That would come out to 151815. If this is right how would I turn this into joules?
 
If that's the right number of molecules (I haven't checked) then that would be the energy in Joules.
 
Thermal energy in one cubic meter of air

Homework Statement



How much thermal energy was in 1 cubic meter of air at room temperature. Give your answer in Joules.

How much kinetic energy does one cubic meter of air have if it were to hit the ground after falling 100 m? Give your answer in Joules.

Which has more energy? Gravitational energy or thermal energy?

Homework Equations



2/3kT

The Attempt at a Solution



So, there are about 2.5 x 10^25 molecules in 1m3 of air. K is 1.381 x 10^-23. I've decided to use 293.15 K as my temperature. The kinetic energy of one molecule is 6.0726 x 10^-21. So, I multiplied by 2.5 x 10^25 would come out to 151815 J, is this thermal energy? How do i calculate the kinetic energy after falling 100m? I'm assuming i just compare the two to answer the third question.
 
I think your calculation of the thermal energy is correct. Can you calculate the mass of 1 m^3 of air? Do you know how to calculate the gravitational potential energy gained when a mass m falls a distance h under the influence of gravity?
 
Bgerst103 said:
So, there are about 2.5 x 10^25 molecules in 1m3 of air. K is 1.381 x 10^-23. I've decided to use 293.15 K as my temperature. So the kinetic energy of one molecule is 6.0726 x 10^-21. So do I multiply this by 2.5 x 10^25? That would come out to 151815. If this is right how would I turn this into joules?

That's already in Joules (You would know that if you kept better track of units. That's a very important point that for some reason most student blow off as unimportant or trivial. Don't make that mistake. Instead of "K is 1.381 x 10^-23" say "kB = 1.381 x 10-23 J/K" Note all the changes I've made to your statement. They were all intentional). I didn't check your math, it but seems to be in the right ball park.
 
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phyzguy said:
I think your calculation of the thermal energy is correct. Can you calculate the mass of 1 m^3 of air? Do you know how to calculate the gravitational potential energy gained when a mass m falls a distance h under the influence of gravity?

The density of air at room temp is about 1.2 kg/m3 so mass would be M=DV so I guess the mass is just 1.2 as well? Gravitional potential energy is just PE=mgh correct? So then, 1.2(9.8)(100)=1176 meaning thermal energy is much greater than gravitational.
 
Bgerst103 said:
The density of air at room temp is about 1.2 kg/m3 so mass would be M=DV so I guess the mass is just 1.2 as well? Gravitional potential energy is just PE=mgh correct? So then, 1.2(9.8)(100)=1176 meaning thermal energy is much greater than gravitational.

I think that's correct.
 

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