Thermal Expansion of a gold ring

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To remove a gold ring with an inner diameter of 2.26 cm from a finger with a knuckle diameter of 2.3 cm, the ring must be heated to expand sufficiently. The coefficient of linear expansion for gold is 1.42 E -5. The circumference of the ring, calculated using the formula C = π * diameter, is approximately 7.09 cm, which represents the initial length for expansion calculations. The key challenge lies in determining how to apply the linear expansion formula, delta L = alpha * Lo * delta T, to find the required temperature increase. Properly applying these principles will yield the necessary temperature to free the ring.
thaixicedxtea
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Homework Statement


You somehow manage to get a gold ring with inner diameter 2.26 cm stuck on your finger, even though your knuckle has a diameter of 2.3 cm. The temperature of the ring is 23 degrees C.
To what temperature would you have to heat the ring in order to get it off your finger? The coefficient of linear expansion of gold is 1.42 E -5. Answer in units of C.


Homework Equations


delta L = alpha/coefficient * Lo * delta T



The Attempt at a Solution


Since I'm given the linear expansion coefficient, I figured that I'm going to use the delta L equation. What I'm stuck with is what to do with the diameters given, like how do I figure out the initial length from the diameter...
 
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thaixicedxtea said:

Homework Statement


You somehow manage to get a gold ring with inner diameter 2.26 cm stuck on your finger, even though your knuckle has a diameter of 2.3 cm. The temperature of the ring is 23 degrees C.
To what temperature would you have to heat the ring in order to get it off your finger? The coefficient of linear expansion of gold is 1.42 E -5. Answer in units of C.


Homework Equations


delta L = alpha/coefficient * Lo * delta T



The Attempt at a Solution


Since I'm given the linear expansion coefficient, I figured that I'm going to use the delta L equation. What I'm stuck with is what to do with the diameters given, like how do I figure out the initial length from the diameter...

What is the circumference of the ring?
 
C equals pi * diameter, so the circumference of the ring is 2.26 cm * pi = 7.09.
Is that the length? If it is, why?
I must be thinking too hard...
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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