Thermal Physics: Kinetic Energy of Neon Molecules

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[SOLVED] thermal physics

Homework Statement

a) What is the total random kinetic energy of all the molecules in one mole of neon at a temperature of 305 K? I got 3801.83J

(b) With what speed would a mole of neon have to move so that the kinetic energy of the mass as a whole would be equal to the total random kinetic energy of its molecules?

Homework Equations

(1/2)mv^2=(3/2)kT
v(rms)=sqrt(3kT/m)

The Attempt at a Solution

I'm not sure what to do in order to solve for part b. Not to sure if I'm even looking at the correct equations. Any suggestions?

Thanks

 

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any suggestions. I would love the help and greatly appreciate it. :)

 

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I figured it out:

KE=1/2(mv^2)

KE=3801.83
m=20.2*10^-3