Thermal radiation in transparent objects

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The discussion centers on the thermal radiation properties of transparent objects, particularly glass. It highlights that while glass is transparent to certain wavelengths, it can still absorb and emit thermal radiation, albeit not as efficiently as a black body. The conversation explores the implications of radiation absorption and emission between objects, emphasizing that if a system has not reached thermal equilibrium, an object can cool down. Participants clarify misconceptions about how radiation interacts between different materials. Ultimately, the complexities of thermal radiation and transparency in materials are acknowledged, leading to a better understanding of the principles involved.
dRic2
Every objects emit thermal radiation. Now consider this case: Sun emits waves in a certian electromagneic spectrum (UV + thermal radiation + ecc...); glass is transparent to thermal radiation that usually reach Earth's surface. UV and other radiations are mainly absorbed by Ozone and other gasses in the atmosphere thus (in a hypotetical scenario) Sun can not transmit energy to glass. SO the piece of glass, which is emitting energy, should be lowering his temperature. It is obviusly not possible, but what did I miss?
 
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dRic2 said:
Every objects emit thermal radiation. Now consider this case: Sun emits waves in a certian electromagneic spectrum (UV + thermal radiation + ecc...); glass is transparent to thermal radiation that usually reach Earth's surface. UV and other radiations are mainly absorbed by Ozone and other gasses in the atmosphere thus (in a hypotetical scenario) Sun can not transmit energy to glass. SO the piece of glass, which is emitting energy, should be lowering his temperature. It is obviusly not possible, but what did I miss?
If an object can radiate at a certain wavelength then equally it can absorb at that wavelength.
My understanding is that most glass does absorb IR quite well, but not equally across the IR band.
 
Ok but if an object A emits radiations F and G (let's call them that way to make it simple) and I place two objects (B and C) in front of him such as B absord F and is transparent to G and C is trasparent to G, how can the radiations of A reach the object C? I think it can not. But C is emetting too so it may get cooler (nonsense).
 
dRic2 said:
Ok but if an object A emits radiations F and G (let's call them that way to make it simple) and I place two objects (B and C) in front of him such as B absord F and is transparent to G and C is trasparent to G, how can the radiations of A reach the object C? I think it can not. But C is emetting too so it may get cooler (nonsense).
Why is it nonsense? If the system has not reached equilibrium then C can cool.
Here's a simpler example: object A only emits/absorbs in band a, the enclosing shell B only emits/absorbs in the disjoint band b. If there is no conduction then each behaves as though the other does not exist. The equilibrium temperature of A will depend on the background radiation in band a beyond the shell.
 
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dRic2 said:
Every objects emit thermal radiation.
Careful here. A piece of glass is NOT a black body. It will not emit as efficiently as a black body at the same temperature.

A black body is an ideal absorber, but it is also a perfect emitter. Any gray body or white body will both absorb and emit less completely.
 
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Dale said:
Careful here. A piece of glass is NOT a black body. It will not emit as efficiently as a black body at the same temperature.

A black body is an ideal absorber, but it is also a perfect emitter. Any gray body or white body will both absorb and emit less completely.

Yeah, but There is no need for this here I think.

haruspex said:
Why is it nonsense? If the system has not reached equilibrium then C can cool.
Here's a simpler example: object A only emits/absorbs in band a, the enclosing shell B only emits/absorbs in the disjoint band b. If there is no conduction then each behaves as though the other does not exist. The equilibrium temperature of A will depend on the background radiation in band a beyond the shell.

Yes, you're right, I was Just thinking a very strange complicated thing (that I won't explain because It would be very hard) but I realized It is not possibile, so now everything fits in place
 

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