(Thermo) Radiation in Cavity. Work and Compression?

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SUMMARY

The discussion focuses on thermodynamic principles related to radiation in a cavity, specifically addressing the relationships between entropy, internal energy, and volume during adiabatic processes. Key equations derived include (ds/dt)v = 1/T[du/dt] and (ds/dv)T = 1/T[du/dv + P], confirming the dependence of entropy on temperature and internal energy. The internal energy is expressed as u(T) = Const*T^4, indicating a fourth power relationship with temperature. The work done during adiabatic expansion is derived in terms of initial and final volumes and temperatures, leading to the equation oTV^(1/3) = Const^1/3.

PREREQUISITES
  • Understanding of thermodynamic principles, specifically adiabatic processes.
  • Familiarity with entropy and internal energy concepts in thermodynamics.
  • Knowledge of calculus for integrating thermodynamic equations.
  • Basic understanding of radiation laws and their application in thermodynamic systems.
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  • Study the derivation of the Stefan-Boltzmann Law for blackbody radiation.
  • Learn about adiabatic processes in ideal gases and their implications.
  • Explore the concept of entropy in greater detail, particularly in relation to thermodynamic cycles.
  • Investigate the relationship between pressure, volume, and temperature in non-ideal gases.
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Homework Statement


U = u(T)V; P=u(T)/3
a. Find (ds/dt)v and (ds/dv)T in terms of u.
Ans. (ds/dt)v = 1/T[du/dt] and (ds/dv)T = 1/T[du/dv + P]...Correct
b. Show that u(T) = Const*T^4
equate partials above and integrate...Correct
c. Find a Relation between V and T during adiabatic compression or expansion of the cavity?
d. The system goes adiabatically from V1 at T1 to V2. Find work done during expansion in terms of V1, V2,T1?

Homework Equations

The Attempt at a Solution


a. Find (ds/dt)v and (ds/dv)T in terms of u.
Ans. (ds/dt)v = 1/T[du/dt] and (ds/dv)T = 1/T[du/dv + P]...Correct
b. Show that u(T) = Const*T^4
equate partials above and integrate...Correct
c/d?
d. maybe dQ=0=> dW = dU
du = du/dt + du/dv
Plug in and integrate get VU + U(V2-V1)?
 
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Solved C. dU = Vdu + idv then vdu+udv = -pdV integrate and simplify to get: oTV^(1/3) = Const^1/3. Now just need d.
 

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