Thermochemistry Help Again How to find mass?

Click For Summary
SUMMARY

The discussion focuses on calculating the mass of boiling water needed to raise the temperature of 25 kg of room-temperature water (25 degrees Celsius) to body temperature (37 degrees Celsius). The key equation used is q = mc(Tf-Ti), where q represents the heat energy, m is the mass, c is the specific heat capacity, Tf is the final temperature, and Ti is the initial temperature. The initial calculations provided by the user were incorrect, leading to confusion regarding the correct mass of boiling water required. The correct approach involves setting up an equation based on the heat gained by the cooler water and the heat lost by the boiling water.

PREREQUISITES
  • Understanding of thermochemistry principles
  • Familiarity with the specific heat capacity of water (4.18 J/g°C)
  • Ability to manipulate algebraic equations
  • Knowledge of temperature scales and conversions
NEXT STEPS
  • Study the concept of heat transfer in thermodynamics
  • Learn how to apply the principle of conservation of energy in thermal systems
  • Explore specific heat capacity calculations for different substances
  • Practice solving problems involving mixed temperatures and mass calculations
USEFUL FOR

Students studying thermochemistry, educators teaching heat transfer concepts, and anyone interested in practical applications of thermal energy calculations.

kirsten_2009
Messages
136
Reaction score
2

Homework Statement



Imagine that your water heater has broken, but you want to take a bath. You fill your bathtub with 25 kg of room-temperature water (about 25 degrees Celsius). You figure that you can boil water on the stove and pour it into the bath to raise the temperature. How much boiling water would you need in order to raise the bath to body temperature (about 37 degrees Celsius)? Assume that no heat is transferred to the surrounding environment.

Homework Equations



q = mc(Tf-Ti)

The Attempt at a Solution



So I find "q" in the following way:

q = 25000 g x 4.18 J/g x C x 12 C
q = 125400 J/g x C

Then, I sub in the following...

m = q/c(Tf-Ti)
m = 125400 J/g x C / 4.18 J/g x C x 12 C
m = 2500

I have a strong feeling this is terribly wrong, can someone please point the mistake out for me?
 
Physics news on Phys.org
kirsten_2009 said:
q = mc(Tf-Ti)

The Attempt at a Solution



So I find "q" in the following way:

q = 25000 g x 4.18 J/g x C x 12 C
q = 125400 J/g x C

Then, I sub in the following...

m = q/c(Tf-Ti)
m = 125400 J/g x C / 4.18 J/g x C x 12 C
m = 2500

I have a strong feeling this is terribly wrong, can someone please point the mistake out for me?

What is that "q = 25000 g x 4.18 J/g x C x 12 C", and why find out the energy of the water?
The specific heat of water between 0 and 100 is about the same.(usually regarded)

So you have 25kg -- 25'C
x kg -- 100'c
And the 25+x kg -- 37'C

Can you get an equation from these?
 

Similar threads

  • · Replies 5 ·
Replies
5
Views
3K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 7 ·
Replies
7
Views
3K
Replies
6
Views
15K
Replies
7
Views
3K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 2 ·
Replies
2
Views
3K
Replies
4
Views
4K
  • · Replies 1 ·
Replies
1
Views
5K
  • · Replies 2 ·
Replies
2
Views
6K