Thermodynamic- Internal energy of dry air

Click For Summary

Homework Help Overview

The discussion revolves around the thermodynamic properties of dry air, specifically focusing on calculating its density and internal energy under given conditions of pressure and temperature.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants explore the relationship between pressure, density, and temperature using the ideal gas equation. There are attempts to derive the density of dry air and questions regarding the correctness of the calculations. Additionally, there is uncertainty about how to approach the calculation of internal energy.

Discussion Status

Some participants have provided initial calculations and are seeking verification of their results. Others are prompting for further thought on the equations involved and offering hints related to the internal energy calculation without providing direct solutions. The conversation reflects a mix of exploration and clarification of concepts.

Contextual Notes

Participants are working under the constraints of specific pressure and temperature values, and there is an indication of confusion regarding the application of the ideal gas law and the formula for internal energy.

harman12345
Messages
2
Reaction score
0

Homework Statement


a) what is the density of dry air when the surface pressure is 1010hPa and the temperature is 27°C.

b) what is the internal energy of 1kg of dry air under these conditions?


Homework Equations


P=p*R*T where P is pressure and p is density.


The Attempt at a Solution


a) p = RT/P by solving it gives me
[287*(273+27)] / 101000 => 0.852kg/m

can someone please check what i did for part (a) is right or not?

b) i don't really get where to go with this question. So some help would be really appreciated thanks!
 
Physics news on Phys.org
harman12345 said:

Homework Equations


P=p*R*T where P is pressure and p is density.


The Attempt at a Solution


a) p = RT/P


Think it over...

ehild
 
ehild said:
Think it over...

ehild

OH my bad! should be p=P/RT right?

and hint for part b please
 
Last edited:

Similar threads

Replies
9
Views
2K
Replies
5
Views
1K
  • · Replies 1 ·
Replies
1
Views
2K
Replies
8
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K
Replies
24
Views
3K
  • · Replies 5 ·
Replies
5
Views
1K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 31 ·
2
Replies
31
Views
6K