[SOLVED] Thermodynamic ( quanity of heat) 1. The problem statement, all variables and given/known data Calculate he quantity of heat that needed to transfer 2,0 kg ice of -10C to steam/vapor of 100C The process in this case take place in a good heat-isolated container with heat capacity of 500J/Kg 2. Relevant equations Q=mcT Q+-ml ? 3. The attempt at a solution Hi this is what i done I find that it takes 225600j to change 1 kg liquid water from 100C to vapor.To find the required heat for the temprature change for the water to change from 100C to vapor: 225600J * 2kg = 451200J For the ice to melt and heat to 100C: 2kg*2100j*110= 462000J !: Not sure if this is the right way to find the ice heat since its a phase change it is done diffrently ? adding these two finds the heat needed to transfer the ice to vapor ? But what do i do about the heat capasity im not sure what to do. It does have a effect but i dont know how.