Thermodynamics - Adiabatic Compression

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SUMMARY

The discussion focuses on the adiabatic compression of a monatomic ideal gas, initially at a pressure of 1.60×105 Pa and a volume of 8.50×10-2 m3, compressed to a final volume of 4.00×10-2 m3. The final pressure is calculated to be 5.63×105 Pa, and the ratio of the final temperature to the initial temperature is determined to be T2/T1 = 1.65. The discussion highlights the challenge of calculating work done in an adiabatic process, emphasizing the relationship between internal energy change and work.

PREREQUISITES
  • Understanding of ideal gas laws
  • Familiarity with thermodynamic principles, specifically adiabatic processes
  • Knowledge of monatomic ideal gas properties
  • Basic calculus for integration in thermodynamic equations
NEXT STEPS
  • Study the derivation of work done in adiabatic processes using the first law of thermodynamics
  • Learn about the specific heat capacities for monatomic gases and their implications in thermodynamics
  • Explore the concept of adiabatic processes in real gases versus ideal gases
  • Investigate the application of the adiabatic process in thermodynamic cycles, such as the Carnot cycle
USEFUL FOR

This discussion is beneficial for students and professionals in physics and engineering, particularly those focusing on thermodynamics, mechanical engineering, and anyone involved in the study of gas behavior under varying pressure and volume conditions.

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A monatomic ideal gas that is initially at a pressure of 1.60×105Pa and with a volume of 8.50×10−2m3 is compressed adiabatically to a volume of 4.00×10−2m3

A) What is the final pressure? - 5.63E5

B) How much work is done by the gas during the compression?

C) What is the ratio of the final temperature of the gas to its initial temperature? - T2/T1 = 1.65



dU = -W
nCvdT = -pdV

The problem I am having is actually knowing how to determine work done in an adiabatic system outside of using the change in internal energy. I am at a loss of what to do.
 
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rude man said:
How about dW = -pdV?

Make that pdV.
 

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