Thermodynamics and Gas expansion

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SUMMARY

The discussion centers on the diffusion of N2O (laughing gas) and tear gas (molar mass 240 g/mol) in a classroom setting with 50 rows of students. To determine which row will experience the effects first, participants suggest using the kinetic theory of gases, specifically the equation KE=3/2 KT for kinetic energy and KE=1/2 mv² for velocity. It is established that assuming a uniform temperature throughout the room is necessary to calculate the relative thermal speeds of the gas molecules, which will dictate the diffusion rates of both gases.

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  • Understanding of kinetic theory of gases
  • Familiarity with molecular mass calculations
  • Knowledge of diffusion principles
  • Basic grasp of thermodynamics concepts
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This discussion is beneficial for students in physics or chemistry, educators teaching thermodynamics, and anyone interested in the practical applications of gas laws and diffusion in controlled environments.

InfernalAsylum
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Here's the Question:
In a Classroom there are 50 rows of students. A container of N20 (laughing gas) was opened at the front row and tear gas (molar mass 240 gm/mole) was opened simultaneously at the rear of the room. Which row of students will be the first to be laughing with tears in their eyes? mm(N)=14 & mm(O)=16
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I thought I could solve it by using KE=3/2 KT and then after finding out the kinetic energy... substitute and solve for Velocity in KE=1/2 mv²
However.. in the problem it doesn't say anything about the temperature in the room so I don't know if i should assume that it's room temperature or if there's another way to solve this... Any help is appreciated.
 
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I think it's safe to assume the temperature is uniform throughout the room. You only need the relative thermal speeds of the molecules to determine where the two "diffusion fronts" will meet.
 

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