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Introductory Physics Homework Help
Thermodynamics Cycle: Gas Temperature and Work Calculation | Homework Solution
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[QUOTE="kelvin56484984, post: 5465003, member: 585070"] [h2]Homework Statement [/h2] I.The gas is heated at constant pressure until the volume is 4.4L at point B II. The gas is cooled at constant volume until the pressure decreases to 1.2 atm III. The gas undergoes an isothermal compression back to point A a) Find the temperature at Point A,B,C b) Find the work done on the gas ,the heat transferred to the gas and the change for each process c) Find W,Q and delta U for the whole cycle[h2]Homework Equations[/h2] [/B] delta U=Q+W PV=nRT 1 atm=1.013x10^5 N/m^2 Cp=5/3R+R [h2]The Attempt at a Solution[/h2] a) pv=nRT Tb=PbVb/nR Tb=2.4*4.4/(1*8.31) * 0.001* 1.013*10^5 =129K Ta=129K/2 =64.5K Tc=129K/2 =64.5K b) Wab=pv =2.4*(4.4-2.2)* 1.013x10^5 *0.001 =535J Qab=n*Cp*deltaT =0.32* 8/3*R *(129-64.5K) =457J U=Q+W delta Uab=457+535 =992J Wbc=0 Since the volume keep unchange Qbc=n*Cv*deltaT =0.32*5/3*R*(64.5K-129K) =-285J U=Q+W U=-285J U=0 Since it is isothermic process Wca=nRTc *ln(Vc/Va) =0.32*8.31*64.5K*ln(4.4/2.2) =118 Q+W=0 Q=-118J c) W=Wab+Wbc+Wca =535+0+118 =653J Q=Qab+Qbc+Qca =457-285-118 =54J deltaU=992-285+0 =707J [/QUOTE]
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Introductory Physics Homework Help
Thermodynamics Cycle: Gas Temperature and Work Calculation | Homework Solution
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