Thermodynamics - Dryness fraction Equations

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SUMMARY

The discussion focuses on calculating the dryness fraction and enthalpy in thermodynamics. The specific volume is determined to be 0.2 m³/kg, leading to a dryness fraction (x) of 0.4311. The enthalpy for superheated steam at 400 kPa and 300°C is given as 3066.8 kJ/kg. The user initially questions which equation to use for calculating h1, either h = hf + (x.hfg) or h = x.hg + (1-x).hf, but later clarifies that the confusion arose from an input error in their calculator.

PREREQUISITES
  • Understanding of thermodynamic properties such as specific volume and enthalpy.
  • Familiarity with the concept of dryness fraction in steam calculations.
  • Knowledge of superheated steam tables and their application.
  • Basic skills in using thermodynamic calculators or software.
NEXT STEPS
  • Study the properties of steam using steam tables for various pressures and temperatures.
  • Learn how to accurately calculate enthalpy using both equations for different scenarios.
  • Explore the implications of dryness fraction on thermodynamic cycles.
  • Investigate the use of software tools for thermodynamic calculations, such as EES (Engineering Equation Solver).
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Students and professionals in mechanical engineering, particularly those specializing in thermodynamics, steam systems, and energy conversion processes.

maserati1969
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Homework Statement
A cylinder fitted with a piston has a volume of 0.1 m3 and contains 0.5 kg of steam at 0.4 MPa. Heat is transferred to the steam until the temperature is 300 °C, while the pressure remains constant. Determine the heat transfer and work done for this process. Neglect the change in kinetic and potential energies.
Relevant Equations
Q-W = Delta U
Q = m(h2 - h1)
h = hf + (x.hfg)
I found the specific volume to be 0.2 m^3/kg (0.1 / 0.5), this gives me a dryness fraction (x) of 0.4311
Then I can use Q = m(h2 - h1)
h2 is just enthalpy for superheated steam at 400kPa and 300 Celsius = 3066.8 kJ/kg
but for h1 do I now use:
h = hf + (x.hfg)
or do I use
h = x.hg + (1-x).hf
I get a different enthalpy value for each and not sure which to use?

Thanks in advance for any help
 
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Sorry, it's the same equation, and I don't get a different answer, I entered it into the calculator incorrectly. Sorry, ignore this question !!
 

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