Thermodynamics- Gauge pressure, moles, molecules

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SUMMARY

The discussion focuses on calculating the number of moles and molecules of oxygen gas in a 4.0 m³ container with a gauge pressure of 8x10^5 Pa at 25 degrees Celsius. The correct formula used is derived from the ideal gas law, where moles are calculated using the equation: moles = (pressure x volume) / (R x temperature), resulting in 1292 moles of oxygen. Additionally, the number of molecules is determined by multiplying the moles by Avogadro's number (6.022E23), yielding approximately 7.78E26 molecules of oxygen.

PREREQUISITES
  • Understanding of the ideal gas law
  • Knowledge of gauge pressure and its implications
  • Familiarity with Avogadro's number
  • Basic algebra for manipulating equations
NEXT STEPS
  • Study the ideal gas law and its applications in thermodynamics
  • Learn about gauge pressure versus absolute pressure
  • Explore the concept of molar volume and its significance
  • Investigate the relationship between temperature and gas behavior
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Students studying thermodynamics, chemistry enthusiasts, and anyone looking to understand gas laws and calculations involving moles and molecules.

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Homework Statement


A 4.0 m^3 container of oxygen gas has a gauge pressure of 8x10^5 Pa at 25 degrees c.
a) how many moles of oxy are present in the containe?r ANS: 1292 moles
b)how many oxy molecules are present? ANS: 7.78E26 oxy
(yes, i have the answers but i don't know how to get to them correcly.)

known:
oxy formula weight= 32

Homework Equations


moles=mass/formula weight
ALso, can you explain to me what gauge pressure has to do with moles.

The Attempt at a Solution


i tried to find how many moles by using the denisty of oxygen, but that doesn't work. please help. i am very confused

Nevermind. i got it(:
 
Last edited:
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moles = pressure x volume / R x temperatureR= 8.3144598moles= 8x10^5 Pa x 4 m^3 / 8.3144598 x 298.15 K= 1292 moles molecules= moles x 6.022E23 = 7.78E26 oxy molecules
 

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